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1. The problem statement, all variables and given/known data

Under the following conditions: C1=C, C2=0, Cx=2C, R2=R3=R, Rx=0, find the magnitude and phase of the sinusoidal current flowing through the galvanometer D (ID) whose internal resistance is neglibly small.

3. The attempt at a solution

We have an unbalanced condition. We can determine ID by means of the Thevenin equivalent circuit:

Steps:

1) get Vth:

VTH = VCB = VC - VB = VAC - VAB

(Z1= 1/jwC, Zx=1/jw2C, Z3=Z2=R)

2) Now let's calculate Zth, which will have a real part (resistor) and imaginary part (capacitor)

ZTH = (Z1 || Z2) + (Zx || Z3)

3) Finally let's form the Thevenin equivalent circuit:

ID = VTH / ZTH

ok, up to this point I think we have got the magnitude of ID. What about the phase ? Since a capacitor delays voltage 90 degrees, I believe that the phase of ID is 90, but I am not sure...

Would this work as a solution?

Thanks in advance...

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# Homework Help: Help on thevenizing a Scheering Bridge

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