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degs2k4
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Help on "thevenizing" a Scheering Bridge
Under the following conditions: C1=C, C2=0, Cx=2C, R2=R3=R, Rx=0, find the magnitude and phase of the sinusoidal current flowing through the galvanometer D (ID) whose internal resistance is neglibly small.
Steps:
1) get Vth:
VTH = VCB = VC - VB = VAC - VAB
(Z1= 1/jwC, Zx=1/jw2C, Z3=Z2=R)
2) Now let's calculate Zth, which will have a real part (resistor) and imaginary part (capacitor)
ZTH = (Z1 || Z2) + (Zx || Z3)
3) Finally let's form the Thevenin equivalent circuit:
ID = VTH / ZTH
ok, up to this point I think we have got the magnitude of ID. What about the phase ? Since a capacitor delays voltage 90 degrees, I believe that the phase of ID is 90, but I am not sure...
Would this work as a solution?
Thanks in advance...
Homework Statement
Under the following conditions: C1=C, C2=0, Cx=2C, R2=R3=R, Rx=0, find the magnitude and phase of the sinusoidal current flowing through the galvanometer D (ID) whose internal resistance is neglibly small.
The Attempt at a Solution
We have an unbalanced condition. We can determine ID by means of the Thevenin equivalent circuit:Steps:
1) get Vth:
VTH = VCB = VC - VB = VAC - VAB
(Z1= 1/jwC, Zx=1/jw2C, Z3=Z2=R)
2) Now let's calculate Zth, which will have a real part (resistor) and imaginary part (capacitor)
ZTH = (Z1 || Z2) + (Zx || Z3)
3) Finally let's form the Thevenin equivalent circuit:
ID = VTH / ZTH
ok, up to this point I think we have got the magnitude of ID. What about the phase ? Since a capacitor delays voltage 90 degrees, I believe that the phase of ID is 90, but I am not sure...
Would this work as a solution?
Thanks in advance...
Last edited: