Help on this accelerated motion problem please

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SUMMARY

The discussion focuses on a physics problem involving two stones dropped from a building, with the second stone dropped 1.31 seconds after the first. The goal is to determine the distance between the two stones when the second stone reaches a velocity of 19.3 m/s. The relevant kinematic equations are applied, specifically using the acceleration due to gravity at -9.8 m/s² to calculate the time for the second stone to reach the specified velocity and subsequently find the displacement of both stones.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of acceleration due to gravity (-9.8 m/s²)
  • Ability to calculate displacement and velocity
  • Familiarity with the concept of relative motion
NEXT STEPS
  • Study the kinematic equations for uniformly accelerated motion
  • Learn how to calculate displacement using initial velocity, final velocity, and time
  • Explore problems involving multiple objects in free fall
  • Review concepts of relative velocity and motion analysis
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Students studying physics, educators teaching kinematics, and anyone interested in solving motion-related problems in classical mechanics.

black_hole
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Homework Statement



A stone is dropped from the roof of a high building. A second stone is dropped 1.31 s later. How far apart are the stones when the second stone has reached a speed of 19.3 m/s?

Homework Equations



well...

stone 1
V0 = 0m/s
vf = unknown
t = unknown
a = -9.8m/s/s
x = trying to find

stone 2
V0 = 0m/s
vf = 19.3m/s
t = unknown
a = -9.8m/s/s
x = trying to find

The Attempt at a Solution



That's all I know.
 
Physics news on Phys.org
For stone two, find t to reach the velocity 19.3 m/s.
Using the kinematic equation, find the displacement of stone 2.
Find the displacement of stone i in time ( t+1.31s )
 

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