[HELP]problem in Second equation of Equilibrium

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The discussion centers on calculating the weight distribution on the wheels of a 2400 lb car with axles 7 ft apart and a center of gravity located 3 ft behind the axle. The relevant equation for this problem is TF1 + TF2 = 0, which represents the equilibrium of torques. Classmates provided potential answers of 686 lb and 514 lb for the weight supported by each wheel, indicating a need for clarification on torque calculations and the appropriate legends for the variables involved.

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[HELP]problem in Second Condition of Equilibrium

1. Homework Statement :

The axles of a 2400 lb car are 7 ft apart. if the centr of gravity of the car is 3 ft behind the axle, how much weight is supported by each of the car's wheels? II
2. Homework Equations

I'm not sure. i scanned my notes, then i found this equation
TF1+TF2=0
3. The Attempt at a Solution

i don't also have any idea about this. but my classmates told me that the answers are 686lb and 514lb

i can't solve for this because i don't know what the appropriate legends for them. whether Torque 1? or whatsoever. :|
 
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i need your help until this day because this is our take home quiz. thanks to those who will solve the problem for me. :)
 

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