- #1

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But i'm stuck at

In those fractions i need Xk-Zk and Zk-Yk in the denominators, not Xk-Yk and Xk-Yk. Thanks in advance

- Thread starter lucasLima
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- #1

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But i'm stuck at

In those fractions i need Xk-Zk and Zk-Yk in the denominators, not Xk-Yk and Xk-Yk. Thanks in advance

- #2

mfb

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Then you just have to transform the denominator and not both parts. Not sure if that is the best approach, but it is the one I would try first.

- #3

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I used somthing similar instead Minkowski, i did (a+b)/(1+a+b) <= a/(1+a) + b/(1+b)

f

- #4

mfb

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I don't think that is a valid transformation with the denominator. You change 1+|g+f| to 1+|g|+|f| which might increase the fraction.

Last edited:

- #5

- #6

mfb

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"reduce" in the last post should be "increase", of course.

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- #8

mfb

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Not in general.

a=2, b=5, c=1

1 = 3 + 4?

a=2, b=5, c=1

1 = 3 + 4?

- #9

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You should use the fact that the function x/(1+x)=1-1/(1+x) is increasing.

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