homeworkhelpls
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Misplaced Homework Thread moved from the technical forums
The discussion revolves around simplifying algebraic expressions, specifically focusing on operations involving exponents and constants. Participants are attempting to clarify their approaches to manipulating these expressions correctly.
Some participants have provided guidance on the correct application of algebraic principles, while others are exploring different interpretations of their calculations. There is an ongoing exchange of ideas without a clear consensus on the best approach.
Participants are grappling with the implications of exponent rules and the simplification of terms, with specific focus on the treatment of constants and the expansion of expressions.
Did you take the cube root of the constant multiplier?homeworkhelpls said:View attachment 31519414) here i tried 3x^3 + 3/8x^3 to to get 27/8x^3 but the answer is 3/2 x^3, why?
That is not correct. You can not simply square the individual terms. Do you know what the general result of ##(a-b)^2## is? Multiply out the square to see what is right.homeworkhelpls said:View attachment 31519615) here i did 9x^3/2 - 1/x^3/2 to get 9x^9/4 - 1/x^3/2 but that's not in the right form, how do i do it correctly?
and for 14 i got it now after doing 3 x by cubed root of 3 x by x^3 all over 2 to get 3/2 x^3, thanks :)FactChecker said:Did you take the cube root of the constant multiplier?
That is not correct. You can not simply square the individual terms. Do you know what the general result of ##(a-b)^2## is? Multiply out the square to see what is right.
A product of both. ##-3x^0 = -3 \cdot x^0 = -3 \cdot 1 = -3##homeworkhelpls said:ok then for 15 i expanded the brackets and got 9x^3/2 -3x^0 - 3x^0 + x^-3/2, I am confused if -3x^0 is equal to -3 or 1, please explain