Help Solving a Volume Expansion Problem

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Homework Help Overview

The discussion revolves around a volume expansion problem involving a liquid in a glass tube. Participants are exploring how the expansion of the glass tube affects the height of the liquid, particularly in the absence of specific dimensions for the tube.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the relationship between the expansion of the glass tube and the resulting change in height of the liquid. There is uncertainty regarding the necessary dimensions and how they influence the calculations. Some express confusion over the equations provided and their applicability to the problem.

Discussion Status

The discussion is ongoing, with participants sharing their thoughts and attempting to clarify the relationships involved. Some have suggested looking at external resources, while others are expressing doubts about the correctness of the equations being referenced.

Contextual Notes

There is a noted lack of specific dimensions for the glass tube, which is impacting the ability to solve the problem effectively. Participants are also grappling with the implications of volume expansion and its effects on height without complete information.

Miike012
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I have no idea how to solve this problem. I feel like I need more information.

For one the new height of the liquid should depends on the volume expansion of the glass tube. I am not given any dimensions of the glass tube other than it's height.

Therefore if I am to believe that only the height of the tube changes then the change in height of the liquid does not depend on the length of expansion of the tube, it would only depend on the expansion of the cross sectional surface area of the tube, But I am not given such information.

Therefore I believe (if only the vertical height of the tube changes) then I will need to compare the change in vertical height to the change in volume of the liquid.

Anyways, I am lost... someone help.
 

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janhaa said:
Maybe you can use this as a manual...

https://www.physicsforums.com/showthread.php?t=369840

The equation in the thread does not give me the correct answer

(The change in height of liquid in the tube I don't believe equal to the change in volume of the liquid over the new area of the tube, which is what the equation is saying. The change in height of liquid should be equal to the change in volume of liquid over the change in area of tube)
 
OK, then you can propably use this relation

[itex]h=\frac{V}{A}=\frac{V_o}{A_o}\left(\frac{1+\beta_l \Delta T}{1+2\alpha_g\Delta T}\right)[/itex]

so you can try and see if it works out...
 
Last edited:

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