Help Solving Equation: 0,5m^4/5 = 2u^1/5

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Homework Help Overview

The discussion revolves around solving the equation 0.5m^(4/5) / u^(4/5) = 2u^(1/5) / m^(1/5). Participants are attempting to understand the steps involved in manipulating this equation to isolate variables.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the method of cross-multiplying and question the interpretation of "crossing out" terms. There is a focus on how to rearrange the equation to isolate m and u, with some participants suggesting different interpretations of the original equation.

Discussion Status

Some participants have provided guidance on manipulating the equation, leading to the expression 0.5m = 2u. However, there are differing opinions on the correctness of the initial equation and the subsequent steps, indicating that multiple interpretations are being explored.

Contextual Notes

There are indications of potential misprints in the original problem statement or solutions, which some participants are questioning. Additionally, there is a mention of formatting issues related to LaTeX code used in the discussion.

storoi1990
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Homework Statement



I need help with this euation:

0,5m^4/5 = 2u^1/5
u^4/5 m^1/5

it's been calculated to be:

0,5m = 2u => m = 4u

i need the calculations inbetween..

So far i have come to think that they cross out 4/5, on one side.

and on the other they have crossed out 1/5.

and they are left with:

0,5m = 2u
u m


But what now?


Note: (u) is supposed to be under 0,5m, and (m) is supposed to be under 2u

Likewise with the one on top of the page.

Homework Equations





The Attempt at a Solution

 
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Your equation seems to be
[tex]\frac{.5m^{4/5}}{u^{4/5}} = \frac{2u^{1/5}}{m^{1/5}}[/tex]

An obvious thing to do would be to multiply both sides by u4/5m1/5. This is equivalent to what is called cross-multiplying. Don't think of this as "crossing out" anything.

From the equation above, you get .5m = 2u. Can you take it from there?
 
Your equation seems to be
LaTeX Code: \\frac{.5m^{4/5}}{u^{4/5}} = \\frac{2u^{1/5}}{m^{1/5}}

An obvious thing to do would be to multiply both sides by u4/5m1/5. This is equivalent to what is called cross-multiplying. Don't think of this as "crossing out" anything.

From the equation above, you get .5m = 2u. Can you take it from there?

yeah, you have typed question wrong. or otherwise there is a misprinting in your book either in question or in solution.

See the answer for your given question
[tex] \frac{0.5m^{4/5}}{u^{4/5}.m^{1/5}} = 2u^{1/5}[/tex]

[tex] \frac{m^{4/5}}{u^{4/5}.m^{1/5}} = 4u^{1/5}[/tex]

[tex] <br /> m^{3/5} = 4u<br /> [/tex]

[tex] <br /> m = (4u)^{5/3}<br /> [/tex]
 
Last edited:
to snshusat:

yes, it's supposed to be the way mark wrote.

how do you write it like that btw?

to mark:

okey so then i get 0,5m^4/5*m^1/5 = 2u^1/5*u^4/5

so: 0,5m^5/5 = 2u^5/5

and then: 0,5m = 2u

and then finally: m = 4u

right?
 
Last edited:
snshusat161 said:
[tex] <br /> m^{3/5} = 4u<br /> [/tex]

[tex] <br /> m = {4u}^{5/3}<br /> [/tex]

Even though the question was different, this is incorrect.

[tex]m^{3/5}=4u[/tex]

[tex]m=(4u)^{5/3}=4^{5/3}u^{5/3}[/tex]

edit: after seeing your latex as {4u}^{5/3} you weren't wrong, but you should have added parentheses around the (4u).
 
thanks for figuring it out, this code is very hard to type.

Edit: I think I should have used () in place on {}. I thought that I've become so expert in typing those codes that I've not reviewed it again after posting. That guy may have got punishment from his teacher if he had copied that solution. Sorry :(
 
Last edited:
snshusat161 said:
That guy may have got punishment from his teacher if he had copied that solution. Sorry :(

Sure he would have! You started with the wrong question :-p
 

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