Help Solving Equation Involving A Rational Exponential

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Captain1024
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Homework Statement


Solve ##y=\mathrm{exp}(\frac{-x\pi}{\sqrt{1-x^2}})## for x when y = 0.1

Homework Equations


##\mathrm{ln}(e^x)=x##

The Attempt at a Solution


##\mathrm{ln}(0.1)=\frac{-x\pi}{\sqrt{1-x^2}}##
##(\frac{-\mathrm{ln}(0.1)}{\pi})^2=\frac{x^2}{1-x^2}##
 
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Captain1024 said:

Homework Statement


Solve ##y=\mathrm{exp}(\frac{-x\pi}{\sqrt{1-x^2}})## for x when y = 0.1

Homework Equations


##\mathrm{ln}(e^x)=x##

The Attempt at a Solution


##\mathrm{ln}(0.1)=\frac{-x\pi}{\sqrt{1-x^2}}##
##(\frac{-\mathrm{ln}(0.1)}{\pi})^2=\frac{x^2}{1-x^2}##
It is all right so far. What is your problem? You got a simple equation for x2.
 
Captain1024 said:

Homework Statement


Solve ##y=\mathrm{exp}(\frac{-x\pi}{\sqrt{1-x^2}})## for x when y = 0.1

Homework Equations


##\mathrm{ln}(e^x)=x##

The Attempt at a Solution


##\mathrm{ln}(0.1)=\frac{-x\pi}{\sqrt{1-x^2}}##
##(\frac{-\mathrm{ln}(0.1)}{\pi})^2=\frac{x^2}{1-x^2}##

One thing that will improve the looks of the right hand side. Recognize that −ln(0.1) is ln( (0.1)−1 )

Another thing you might try is to take the reciprocal of both sides of the equation.
 
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SammyS said:
One thing that will improve the looks of the right hand side. Recognize that −ln(0.1) is ln( (0.1)−1 )

Another thing you might try is to take the reciprocal of both sides of the equation.
##x=\sqrt{\frac{1}{\frac{\pi ^2}{(\mathrm{ln}(10))^2}+1}}##

That's what I needed. Thank you.