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Help Solving Percent Molarity Problem

  1. Feb 19, 2012 #1
    I have to prepare the following solution:

    200 mL of 2.5% Glutaraldehyde from 25% stock Glutaraldehyde in 0.2M Sodium Cacodylate Buffer

    So far I know:

    Molecular weight of Glutaraldehyde: 100g/mol and Sodium Cacodylate:160g/mol

    Assuming the density is 1 of Glutaldehyde, then 25%(1000g)=250g
    250g/molecular weight(100g/mol)= 2.5mol/L-->2.5M

    After this I have no clue which way to go. Any help would be great.
  2. jcsd
  3. Feb 19, 2012 #2


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    Use M1V1=M2V2. Don't need to go back to moles, percentages are fine.
    Last edited by a moderator: Feb 20, 2012
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