I have to prepare the following solution:(adsbygoogle = window.adsbygoogle || []).push({});

200 mL of 2.5% Glutaraldehyde from 25% stock Glutaraldehyde in 0.2M Sodium Cacodylate Buffer

So far I know:

Molecular weight of Glutaraldehyde: 100g/mol and Sodium Cacodylate:160g/mol

Assuming the density is 1 of Glutaldehyde, then 25%(1000g)=250g

250g/molecular weight(100g/mol)= 2.5mol/L-->2.5M

After this I have no clue which way to go. Any help would be great.

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# Homework Help: Help Solving Percent Molarity Problem

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