Help Solving Trig Homework: Find cos(u+v)

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Homework Help Overview

The discussion revolves around finding cos(u+v) given specific values for sin(u) and cos(v), along with defined ranges for the angles u and v. The problem is situated within the context of trigonometric identities and angle addition formulas.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the given trigonometric values and the cosine of the sum of angles. There is uncertainty about whether to simply add the cosine values or apply a specific formula. One participant suggests using the angle addition identity for cosine.

Discussion Status

There is a mix of attempts to apply the angle addition identity, with one participant providing a calculation based on the identity. However, the discussion does not reach a consensus, as another participant expresses uncertainty about the simplicity of the problem.

Contextual Notes

Participants are working under the constraints of the given ranges for u and v, which may influence the signs of the trigonometric functions involved.

e^(i Pi)+1=0
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Homework Statement



If Sin(u)=[itex]\frac{\sqrt{2}}{2}[/itex] and cos(v)=[itex]\frac{4}{5}[/itex] and

0≤ u ≤[itex]\frac{∏}{2}[/itex] and [itex]\frac{3∏}{2}[/itex]≤ v ≤ 2∏

find cos (u+v)

The Attempt at a Solution



cos(u)=[itex]\frac{\sqrt{2}}{2}[/itex] and cos(v)=[itex]\frac{4}{5}[/itex]

Do I just add them together? I feel like I'm missing something, but maybe the problem really is that simple.
 
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e^(i Pi)+1=0 said:

Homework Statement



If Sin(u)=[itex]\frac{\sqrt{2}}{2}[/itex] and cos(v)=[itex]\frac{4}{5}[/itex] and

0≤ u ≤[itex]\frac{∏}{2}[/itex] and [itex]\frac{3∏}{2}[/itex]≤ v ≤ 2∏

find cos (u+v)

The Attempt at a Solution



cos(u)=[itex]\frac{\sqrt{2}}{2}[/itex] and cos(v)=[itex]\frac{4}{5}[/itex]

Do I just add them together? I feel like I'm missing something, but maybe the problem really is that simple.
Use the angle addition identity for cosine .
 


So it would be..

([itex]\frac{\sqrt{2}}{2}[/itex])([itex]\frac{4}{5}[/itex])-([itex]\frac{\sqrt{2}}{2}[/itex])([itex]\frac{-3}{5}[/itex]) = [itex]\frac{7\sqrt{2}}{10}[/itex]
 


Excellent!

ehild
 

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