Help Understand Retarded Function: Einstein Eq. Linearized

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The discussion centers on the linearization of the Einstein equations, resulting in the weak field Einstein equations represented by the equation $$\left ( -\frac{\partial^{2}}{\partial t^{2}} + \nabla^{2} \right ) \bar h^{\mu\nu}=-16\pi T^{\mu\nu}$$. The Retarded function serves as a solution, expressed as $$\bar h^{\mu\nu} (t,\vec x)=4 \int d^{3}x' \frac{[T^{\mu\nu}(t',\vec x')]_{[ret]}}{|\vec x - \vec x'|}$$, where $$t' = t_{ret} = t-|\vec x - \vec x'|$$. The discussion clarifies that $$|\vec x - \vec x'|$$ represents the spatial separation between the observation point and the source, analogous to the concept in electromagnetism.

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Hi people, help here please
When the Einstein equation are linearized the results are the weak field Einstein equations

$$
\left ( -\frac{\partial^{2}}{\partial t^{2}} + \nabla^{2} \right ) \bar h^{\mu\nu}=-16\pi T^{\mu\nu}
$$
a solution for this equations considering the source are the Retarded function
$$
\bar h^{\mu\nu} (t,\vec x)=4 \int d^{3}x' \frac{[T^{\mu\nu}(t',\vec x')]_{[ret]}}{|\vec x - \vec x'|}
$$
with

$$t' = t_{ret} = t-|\vec x - \vec x'|$$

until i know "t" and "x" in spacetime are the same but what physical situation describes
$$
|\vec x - \vec x'|
$$
Is similar to electromagnestism, when $$\vec x$$ represent the place where you want calculate the potencial and $$\vec x'$$ represent the place where the charge is located?

Thanks in advance
 
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Your weak field equation is just a separate wave equation for every individual component. The solution is just applying the retarded Green's function of the wave equation.
 
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