Help! Understanding Adding/Subtracting Vectors in i, j, k

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SUMMARY

This discussion focuses on the addition and subtraction of vectors represented in the i, j, k format, specifically addressing the calculation of vector lengths. The key method for finding the magnitude of a vector is the Pythagorean theorem, applied to the components of the vector. For example, the length of the vector 16i - 32j + 25k is calculated as √(16² + (-32)² + 25²), resulting in approximately 43.6. Additionally, the discussion emphasizes that vector addition is performed component-wise, allowing for straightforward calculations.

PREREQUISITES
  • Understanding of vector notation (i, j, k)
  • Familiarity with the Pythagorean theorem
  • Basic knowledge of Cartesian coordinates
  • Ability to perform arithmetic operations with real numbers
NEXT STEPS
  • Study vector addition and subtraction using component-wise methods
  • Learn how to calculate the magnitude of vectors using the formula √(x² + y² + z²)
  • Explore the conversion between Cartesian coordinates and polar coordinates
  • Practice solving problems involving vectors in three-dimensional space
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Students preparing for exams in physics or mathematics, educators teaching vector concepts, and anyone seeking to improve their understanding of vector operations in three-dimensional space.

lanzjohn
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Hello,

I am studying for a test I have on Monday and in my class we briefly went over adding and subtracting vectors in the y, x, and z components or in other words the i, j, and k.

The problem is I do not understand how to add and subtract problems like these to find the length:

32j + 30 k

or 16i-32j-25k

I looked through my books and notes and I can't figure it out. I also don't know how to find the length of something like

45i

Thanks for helping me out its driving me crazy trying to make sense of these things.
 
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lanzjohn said:
Hello,

I am studying for a test I have on Monday and in my class we briefly went over adding and subtracting vectors in the y, x, and z components or in other words the i, j, and k.

The problem is I do not understand how to add and subtract problems like these to find the length:

32j + 30 k

or 16i-32j-25k

I looked through my books and notes and I can't figure it out. I also don't know how to find the length of something like

45i

Thanks for helping me out its driving me crazy trying to make sense of these things.

Mostly it's using the Pythagorean theorem to find the magnitude, and a little trig to convert between "rectangular" or "Cartesean" (i,j,k) coordinates and Magnitude/Direction coordinates.

http://en.wikipedia.org/wiki/Polar_coordinate_system

http://en.wikipedia.org/wiki/Rectangular_coordinates

The length (magnitude) of 45i is 45, and the direction is pointing in the +x axis direction.

For other vectors that several rectangular components, use the conversion techniques described in the wikipedia article. Hope that helps.
 
lanzjohn said:
Hello,

I am studying for a test I have on Monday and in my class we briefly went over adding and subtracting vectors in the y, x, and z components or in other words the i, j, and k.

The problem is I do not understand how to add and subtract problems like these to find the length:

32j + 30 k

or 16i-32j-25k

I looked through my books and notes and I can't figure it out. I also don't know how to find the length of something like

45i

Thanks for helping me out its driving me crazy trying to make sense of these things.
The whole point of using "i", "j", and "k" is that addition and subtraction can be done "component wise". That is (ai+ bj+ ck)+ (ui+ vj+ wk)= (a+ u)i+ (b+ v)j+ (c+ w)k.
In particular, 32j+ 30k (the coefficient of i is 0) added to 16i- 32j- 25k is (0+ 16)i+ (32-32)j+ (30- 25)k= 16i+ 0j+ 5k= 16i+ 5k.

The length of the vector xi+ yj+ zk is [itex]\sqrt{x^2+ y^2+ z^2}[/itex]
In particular, the length of just xi is [itex]\sqrt{x^2}= |x|[/itex].
The length of 16i- 32j+ 25 k is [itex]\sqrt{16^2+ (-32)^2+ 25^2}= \sqrt{256+ 1024+ 625}= \sqrt{1905}[/itex] which is about 43.6. The length of 45j is |45|= 45.
 

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