Help with 2 simple highschool physics Problem

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SUMMARY

The discussion focuses on solving two high school physics problems involving average speed and distance. For the first problem, to average 60 km/h over a 90-km trip after averaging 40 km/h for the first 40 km, the required speed for the remaining 50 km is calculated to be 100 km/h. The second problem requires determining the speed needed to catch up to Juanita, who has been walking at 4.5 km/h for 45 minutes. To catch up in one hour, the required speed is 9 km/h.

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  • Understanding of average speed calculations
  • Familiarity with basic physics equations (v = d/t)
  • Ability to convert time into hours and minutes
  • Knowledge of distance and time relationships
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  • Study average speed problems in physics
  • Practice solving distance-time-speed equations
  • Explore real-world applications of average speed calculations
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High school students studying physics, educators teaching kinematics, and anyone looking to improve their problem-solving skills in average speed scenarios.

pamba
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:redface: I am really tired and i can't sem to thik right. Please help with these 2 questions




Homework Statement



1. If you must average 60 km/h for a 90-km trip, and only average 40 km/h for the first 40 km, wha velocity must you average the rest of the way?

2. Juanita left on a walk 45 min ago. She is traveling a 4.5km/h. How fast must you travel to catch up to her in 1.0 h?


Homework Equations



v: d/t


The Attempt at a Solution



??
 
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1. How much time would it take if you were going 90km at 60km/h?
How much time have you spent going 40km/h?
So how fast will you have to go for the next 50km in the time you have left?
 
#2

As for #2, how much has Juanita traveled in 45 minutes?
How much will she have traveled once you have caught up to her? (in 1 hour and 45 mins)

that should help
qk
 

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