Help with a Geometry Problem - Calculating The Radius of a Curve

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The discussion centers on calculating the radius of a curve using a chord length and versine in transport engineering. A formula is presented, suggesting that the versine in millimeters divided by 50,000 yields the radius in meters. There is confusion regarding the use of a negative sign in the example provided, which may not be necessary. Clarification is offered, directing users to a resource that explains the correct application of the formula. Ultimately, using a versine of 25mm and a chord length of 20m correctly leads to a radius of 2000m.
tomtomtom1
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Hello all

I work in transport engineering. i have come across what seems to be a simple maths problem but i do not understand it.

The problem relates to geometry i.e. calculating the radius of a curve using a chord and a versine.

The problem is this:-

" a general rule of thumb is as follows: with a chord length on 20m, the versine measured in mm (v) divided by 50000 gives the radius in meters (R) i.e. v=25mm -25/50000=2000-R=2000m"

when i work this out i do not get 2000m. also the problem shows a -25 it could be a minus or just a dash i cannot be sure.

Can anyone shed any light on this?

Thank you for your help
 
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tomtomtom1 said:
Hello all

I work in transport engineering. i have come across what seems to be a simple maths problem but i do not understand it.

The problem relates to geometry i.e. calculating the radius of a curve using a chord and a versine.

The problem is this:-

" a general rule of thumb is as follows: with a chord length on 20m, the versine measured in mm (v) divided by 50000 gives the radius in meters (R) i.e. v=25mm -25/50000=2000-R=2000m"

when i work this out i do not get 2000m. also the problem shows a -25 it could be a minus or just a dash i cannot be sure.

Can anyone shed any light on this?

Thank you for your help

Well, your confusion is justified. It's an incoherent mess. None of those minus signs is a minus sign. Check the page www.mathopenref.com/arcradius.html and you should understand what is happening. Following the symbols used on that page, plug in a versed sine of H=25mm and a chord length of W=20m and you get the desired result of R=2000m.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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