Help with a question about collinear points

  • Thread starter Thread starter mathstudent88
  • Start date Start date
  • Tags Tags
    Points
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
mathstudent88
Messages
25
Reaction score
0
Let P1, P2, ..., P5 be five points, no three of which are collinear. How many lines contain two of these five points?


How I thought about solving this was by way of combinations.

C5,2= (5*4*3*2)/2 = 60.


So there would be 60 lines that contain 2 of the 5 points. Is this a good way to approach this problem or is there a better way?

Thank you for your help!
 
Last edited:
Physics news on Phys.org
Welcome to PF!

Hi mathstudent88! Welcome to PF! :smile:

(hmm … 60 is a very large number … :rolleyes:)
mathstudent88 said:
Let P1, P2, ..., P5 be five points, no three of which are collinear. How many lines contain two of these five points?

How I thought about solving this was by way of combinations.

C5,2= (5*4*3*2)/2 = 60.

So there would be 60 lines that contain 2 of the 5 points. Is this a good way to approach this problem or is there a better way?

No … combinations is exactly the right way! :smile:

but … C5,2 = 5!/2!(5-2)! = … ? :wink:
 
haha I forgot all about the (5-2)! part... thank you for pointing it out for me!

the answer is 10.


Thanks again!