Help with beginner level physics word problem

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SUMMARY

The discussion centers on calculating the height of a human pyramid formed by 30 people and the force exerted on the base person's legs. The formula Fg = mg is highlighted, where Fg represents the gravitational force, m is the mass, and g is the acceleration due to gravity (9.81 m/s²). A participant outlines their approach to constructing the pyramid and seeks clarification on calculating the downward force on the base person, emphasizing the need to consider weight distribution among the layers of the pyramid.

PREREQUISITES
  • Understanding of basic physics concepts, specifically force and weight calculations.
  • Familiarity with the formula W = mg for calculating weight.
  • Knowledge of gravitational acceleration (9.81 m/s²).
  • Basic principles of torque and weight distribution in structures.
NEXT STEPS
  • Research how to calculate the total weight of a structure using W = mg.
  • Learn about weight distribution in multi-layered structures, particularly in human pyramids.
  • Study the concept of torque and its application in analyzing forces in static structures.
  • Explore practical examples of force distribution in physics problems involving multiple layers of weight.
USEFUL FOR

Students studying physics, particularly those tackling problems related to force, weight distribution, and structural analysis. This discussion is beneficial for anyone interested in applying physics concepts to real-world scenarios.

ohenryu
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1.The semester just started and my teacher has assigned us this question: How high of a tower could you build from the people in this class(30 people)? Include diagram. How much force would be pushing down on one of the base person's legs?

2. Note : Fg = mg

3. Here is my work so far : https://fbcdn-sphotos-h-a.akamaihd...._=1423753387_e3fafa257d6be865db2e4a070b88de0e

I created a triangular shape(human pyramid) with 7 people on bottom then 6,5,4,3,2,1,1,1 <- the 1's are on each other shoulders. So far I have calculated the approximate height if the bottom 6 rows are on their hands and knees and if the top 3 are standing up.

The next part is what I need help with. How would I start calculating the force pushing down? I assumed the 2nd row pushing down on the guy at the base would be 2 halves (weight distributed evenly) and so on. I also assumed the height and weight would decrease as the tower went up. I know the force of gravity is 9.8 but how would I use that and Fg = mg in this situation?

I hope you can understand this and help me as I am really confused right now D:
 
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ohenryu said:
The next part is what I need help with. How would I start calculating the force pushing down? I assumed the 2nd row pushing down on the guy at the base would be 2 halves (weight distributed evenly) and so on. I also assumed the height and weight would decrease as the tower went up. I know the force of gravity is 9.8 but how would I use that and Fg = mg in this situation?

I hope you can understand this and help me as I am really confused right now D:

I don't know where you got the equation Fg = mg.

The weight of a person is calculated using W = mg, where m is the mass of a person in kg, g is the acceleration due to gravity, 9.81 m/s2, and W is the weight in Newtons, the SI unit of force.

For example, if someone has a mass of 50 kg, his weight is 50 * 9.81 = 490.5 Newtons. That's a force of 245.25 Newtons on each leg.

To find out the force acting on each row, add up the mass of all the people standing on the rows above.
 
Perhaps by Fg you mean Fg, i.e. the force due to gravity?
The equal distribution is not realistic. Think of them as facing you. The left hand person (your left hand) in the row of two has someone standing on her left shoulder. To spread that weight evenly between her own two feet would involve leaning out to her right. Standing normally, that person could spread her own weight evenly, but transmit all the weight from above to the left foot only. You could analyse the torques.
So in the bottom row, there will be more weight in the centre than on the edges.
 

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