- #1

sneaky666

- 66

- 0

## Homework Statement

suppose Fy(y)=y^3 for 0<=y<1/2 and Fy(y)=1-y^3 for 1/2<=y<=1. Compute these.

1.

P(1/3<Y<3/4)

2.

P(Y=1/3)

3.

P(Y=1/2)

## Homework Equations

## The Attempt at a Solution

Is this right for the 1. ?

P(1/3<Y<3/4)

P(1/3<Y<1/2) + P(1/2<=Y<3/4)

( Fy(1/2-) - Fy(1/3) ) + ( Fy(3/4-) - Fy(1/2-) )

Fy(1/2-) - Fy(1/3) + Fy(3/4-) - Fy(1/2-)

Now I have to use

Fy(y)=y^3 for 0<=y<1/2 and Fy(y)=1-y^3 for 1/2<=y<=1

1/8 - 1/27 + 37/64 - 1/8

=935/1728

for 2 i am getting 1/27

for 3 i am getting 7/8

I think there's something wrong, but I don't know what.