- #1
sneaky666
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Homework Statement
suppose Fy(y)=y^3 for 0<=y<1/2 and Fy(y)=1-y^3 for 1/2<=y<=1. Compute these.
1.
P(1/3<Y<3/4)
2.
P(Y=1/3)
3.
P(Y=1/2)
Homework Equations
The Attempt at a Solution
Is this right for the 1. ?
P(1/3<Y<3/4)
P(1/3<Y<1/2) + P(1/2<=Y<3/4)
( Fy(1/2-) - Fy(1/3) ) + ( Fy(3/4-) - Fy(1/2-) )
Fy(1/2-) - Fy(1/3) + Fy(3/4-) - Fy(1/2-)
Now I have to use
Fy(y)=y^3 for 0<=y<1/2 and Fy(y)=1-y^3 for 1/2<=y<=1
1/8 - 1/27 + 37/64 - 1/8
=935/1728
for 2 i am getting 1/27
for 3 i am getting 7/8
I think there's something wrong, but I don't know what.