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## Homework Statement

A subway train starting from rest leaves a station with a constant acceleration. At the

end of 7.8 s, it is moving at 11.778 m/s. What is the train’s displacement in the ﬁrst 5.6394 s of motion? Answer in units of m

## Homework Equations

a= velocity final - velocity initial / time

delta x = velocity initial(time) + 1/2 (a)(t)^2

## The Attempt at a Solution

delta x = 0 (7.8)+ 1/2 (1.51)(7.8)^2

delta x = 1/2 91.8684

delta x = 45.9342

that is delta x for 7.8 seconds. how do i find delta x for 5.6394 seconds?