Help with force question? i dont know how to get the right answer?

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To find the forces exerted by each lifeguard on the raft, the equations F1 + F2 = 304 N and F1 - F2 = -115 N can be solved simultaneously. By adding these two equations, the result is 2F1 = 189 N, leading to F1 = 94.5 N for the larger force. Substituting F1 back into either equation allows for the calculation of F2, resulting in F2 = 209.5 N for the smaller force. This method effectively utilizes algebraic manipulation to determine the individual forces. The discussion emphasizes the importance of combining equations to solve for unknowns in physics problems.
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Two lifeguards pull on ropes attached to a raft. If they pull in the same direction, the raft experiences a net external force of 304 N to the right. If they pull in opposite directions, the raft experiences a net external force of 115 N to the left.

Find the force exerted by each lifeguard on the raft. (Disregard any other forces acting on the raft.)
____N( larger force)
____N( smaller force)



ive set it up at F1 + F2 = 304 and F1 - F2 = -115 , but i don't know what to do with that, how am i supposed to find the forces? i feel like I am just forgetting a simple math tool haha
 
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snash1057 said:
ive set it up at F1 + F2 = 304 and F1 - F2 = -115 , but i don't know what to do with that, how am i supposed to find the forces? i feel like I am just forgetting a simple math tool haha

So let's call

F1+F2=304 ...eq'n 1

F1-F2=115...eq'2

What happens if we add eq'n 1 to eq'n 2 :wink:?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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