Help with my Non-Standard Gears.

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Discussion Overview

The discussion revolves around the design and mathematical modeling of non-standard gears, specifically focusing on the relationship between a pinion gear and a spur gear. Participants explore methods for ensuring proper tooth contact and aesthetic design, while also addressing challenges in calculating the correct angles for gear rotation.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant, Bill, describes his approach to designing a spur gear to match the profile of an 8-tooth pinion gear, emphasizing the need for good contact despite the gear not carrying any load.
  • Bill details his method of calculating the rotation angles for the gears, expressing uncertainty about the accuracy of his increments and seeking assistance with the mathematics involved.
  • Another participant recalls a previous thread about non-standard gears and suggests searching for software that may assist in gear design, indicating a potential resource for Bill.
  • Several participants express a desire to find links to past discussions on non-standard gears, highlighting the community's interest in shared resources.
  • A later participant shares a simplified method for calculating the movement of pinion teeth around the main gear, claiming success in creating gears using this approach, but does not confirm its universal applicability.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best method for calculating gear profiles, as Bill's original approach is questioned and later refined by another participant. The discussion remains open with multiple perspectives on gear design and calculation methods.

Contextual Notes

Bill's calculations involve assumptions about gear rotations and increments that may not be universally applicable. The discussion includes references to previous threads and external resources that may not be fully accessible to all participants.

Who May Find This Useful

Individuals interested in gear design, mechanical engineering, and those working on non-standard gear applications may find the insights and shared methods beneficial.

Lttlcheeze
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This may be simple to some, but this is my first experience with designing gears, so bear with me...

I'm trying to "cut" a spur gear to match the profile of the pinion gear I designed. This gear won't carry any load, it's basically for esthetics, but I want good contact between the two gears.

I have an 8 tooth pinion & 60 tooth spur gear.
Here is my pinion gear:
untitled_zps3f730a44.jpg


I am working with one tooth profile and trying to simulate it moving out of the mating gear. Seems simple enough...

This is the shape of one tooth, and the line/arc segments are something I drew that approximates what I should end up with (I used the assembly and adjusted the points until it was close).
Untitled_1_zpse920e356.jpg


I could just use those line segments, but I really want to figure this out mathematically.

This is what I figured should be right, but obliviously it's not...
-I drew a circle around the main gear with a radius of the distance between my gear shafts.
-Keeping the center of the pinion gear tooth coincident with that circle I rotated it 5 degrees (I plan on making this increment smaller once I get the calculation figured out).
-Then I rotated the tooth around the center of the spur gear at the increment that it would rotate if the pinion rotated that 5 degrees.
That was .6666666667 degrees. My math:
60 tooth spur - 8 tooth pinion
1 rotation = 7.5 rotations
360 degrees = (360 * 7.5) 2700 degrees
2700 / 5 (sketch increment) = 540
360 / 540 = .666666667

I'm sure I’m over simplifying this because here is my result:
Untitled_2_zpse7eda389.jpg

The red line is the line/arc that represents where I should be.

I know it's really cluttered, but I figure once I get this figured out I can just use this file as a template.

So obliviously .66666667 is too much of an increment.

Just playing with the numbers I found .59 is really close to what I need. But I don't know how to get there mathematically.
Untitled_3_zpscdeb415c.jpg


Does anyone know if I'm just completely over simplifying this, or am I doing something wrong in the math?

Please help!

Thanks,
Bill

Not sure if it will work but I also attached a .gif depicting what I'm trying to accomplish.
generation.gif
 
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We had a thread about non-standard gears (even more exotic) a while ago in this forum, but I cannot find it any more :(. One user presented a software to design those gears in that thread. Maybe you can find it with the search function ("non-standard gears" and "gear software" and 1-2 other queries did not work).
 
mfb said:
We had a thread about non-standard gears (even more exotic) a while ago in this forum, but I cannot find it any more :(. One user presented a software to design those gears in that thread. Maybe you can find it with the search function ("non-standard gears" and "gear software" and 1-2 other queries did not work).

If anyone has a link to this discussion, I would greatly appreciate them posting it. I've done extensive searching and can't seem to find it.
 
The first two figures in this paper are about asymmetric gears. It might be helpful.
 
Awesome mfb, thanks for that. I emailed the developer, hopefully something will come of it.
 
Well I've figured it out. So for anyone else trying to draw odd gears here it is. And it's rather simple...

The Movement of the Pinion Tooth Around the Main Gear is this:
360 / Nm = Tm (Nm=Number of Teeth on Main Gear, Tm=Angle Between Teeth on Main Gear)
Tm / X = M (X=Increment Factor, M=Increment Around Main Gear)

And for the Pinion:
360 / Np = Tp (Np=Number of Teeth on Pinion Gear, Tp=Angle Between Teeth on Pinion Gear)
Tp + Tm = Y
Y / X = P (X=Increment Factor, M=Increment Around Pinion Gear)

So from my original post:
Main Gear is 60t, Pinion is 8t
360 / 60 = 6 / 12 = .5 (I drew 20 teeth and linked them, and with the increment factor set at 12, the 20th tooth was just outside the main gear max OD, so I had plenty of steps inside to cut a good profile)
360 / 8 = 45 + 6 = 51 / 12 = 4.25

As I drew it, each tooth is rotated around the center of the main gear .5 deg.

Then the C/L of each tooth is rotated 4.25 deg. from the last.

That's it plain n simple. I've already made a few gears using this and it works every time.
 

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