1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Help with pool ball pyramid problem

  1. May 11, 2008 #1
    Three identical spheres lie in contact with one another on a horizontal plane. A fourth
    sphere rests on them, touching all three. Show that, in equilibrium, the coefficient of
    friction between the spheres is at least (rad(3)-rad(2)) and that the coefficient between each sphere and the plane is at least (rad(3)-rad(2))/4

    The only thing I can think to use here is summing forces. But woah, I am so stuck. Do I have the right idea even? Any help would be appreciated it!

    Thanks!
     
  2. jcsd
  3. May 11, 2008 #2
    Thats pretty intense!
    I'm having trouble conceptualizing why there has to be any friction between the spheres... but i think i can help with the second part:
    The weight of the top sphere is the only one disrupting equilibrium right? i.e. no top sphere, no motion (even without friction).
    How much top sphere (TS) weight is on each bottom sphere (BS)?
    How much is parallel to the plane they're resting on?
    How much friction is required to balance that - keeping them all stationary?
     
  4. May 11, 2008 #3
    Uh I'm having troubles grasping this. Ok so using what you said before about the second part, I summed forces on one ball.

    (1) In the x: (mg/3)cos(theta)=N(cf) mg/3 is the weight of the top ball on the bottom sphere, N is the normal force at floor, and (cf) is my coefficient of friction.

    (2) In the y: N=mgsin(theta)+mg

    Putting (2) into (1):
    (mg/3)cos(theta)=(cf)(mgsin(theta)+mg)
    reduced:
    cf=cos(theta)/(3sin(theta)+3)

    Is this the right equation to work with? If I knew what angle to put in anyway!
     
  5. May 11, 2008 #4
    Those look correct.
    As for theta... thats just a little geometry.
    The pyramid will be a tetrahedron, i'm sure you can look up or derive the angle somehow... I'm terrible with 3d geo.
     
  6. May 11, 2008 #5
    Yeah I'm awful at it as well I found some angles online like 55 degrees and 71 degrees but neither of them get me to the correct answer given in the question. could it be because I need another force for the friction between the top ball and bottom ball? If so I just get more lost because in introduces a new cf
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Help with pool ball pyramid problem
  1. Pool balls (Replies: 5)

  2. Three Pool Balls (Replies: 1)

Loading...