- #1
kenshaw93
- 10
- 0
Hi I've got this problem which has really been bothering me.
How are you supposed to prove that:
(Sin[A] Sin[2 A] + Sin[3 A] Sin[6 A])/(Sin[A] Cos[2 A] + Sin[3 A] Cos[6 A]) is identicle to tan[5A].
I am almost sure that I've got to use the factor formulae, but I've had no luck. Maybe someone can help me please :)
Thank you for your time!
How are you supposed to prove that:
(Sin[A] Sin[2 A] + Sin[3 A] Sin[6 A])/(Sin[A] Cos[2 A] + Sin[3 A] Cos[6 A]) is identicle to tan[5A].
I am almost sure that I've got to use the factor formulae, but I've had no luck. Maybe someone can help me please :)
Thank you for your time!