Help with proving irrationality

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Homework Help Overview

The discussion revolves around proving the irrationality of square roots and more generally, roots of natural numbers, specifically focusing on the conditions under which these roots are rational or irrational. The subject area includes number theory and properties of prime numbers.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the possibility of using proof by contradiction to show that if the square root of a number is rational, then certain conditions about that number must hold. There is also mention of assuming the existence of a rational representation for the square root and exploring implications regarding prime factors.

Discussion Status

Some participants have begun to outline potential proof strategies, including assumptions about rational representations and the implications of prime factorization. There is an ongoing exploration of the relationship between the conditions of the number and the rationality of its root, with no consensus yet reached.

Contextual Notes

Participants are grappling with the definitions and properties of prime numbers as they relate to the problem, and there is mention of specific cases where the roots may be rational or irrational based on the form of the number involved.

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From Spivak's 4th edition

I'm having some difficulties knowing how to prove these things I need to prove. If someone could help me out, I would appreciate it.


Homework Equations



The book defines a prime number as this: A natural number p is called a prime number if it is impossible to write p=ab for natural numbers a and b unless one of these is p, and the other 1. If n>1 is not a prime, then n=ab, with a and b both < n, if either a or b is not a prime it can be factored similarly.

Homework Statement



I got a fine but then

A fundamental theorem about integers states that this factorization (was talking about factoring stuff down to primes in previous problem) is unique except for the order of the factors. Thus, for example, 28 can never be written as a product of primes one of which is 3, nor can it be written in a way that involves 2 only once.

b. Using this fact, prove that sqrt(n) is irrational unless n = m2 for some natural number m.

c. Prove more generally that ksqrt(n) is irrational unless n = mk


I am so confused on what to do, and how that fact helps me? I was thinking of trying to do a proof by contradition, and attempt to show that sqrt(n) is rational? But I'm not sure how to do this because then I could just prove n=m2. i have no idea how to show that if n =/= m2, sqrt(n) is irrational. Please help.
 
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Does this mean anything at all for b?

Proof by contradiction. Assume sqrt(n) is rational and n=/=m2 for any rational m.

sqrt(n) = p/q where p,q are rational numbers.

if n =/= m2, p/q =/= m. A rational number over a rational number has to rational. =><=
 
You've got the right start. Assume sqrt(n) rational. So n=(a/b)^2. You can also assume a and b have no common prime factors (otherwise you could just divide them out and get a/b in 'lowest terms'). Now that means b^2*n=a^2. Suppose a prime p divides b. Then it also divides a^2 which means it divides a. But we assumed it doesn't. So b isn't divisible by any primes. What is b?
 
there's a part in the book above that question about proving the irrationality of cube root, square root, 5-root.. et c and then it tells you to think about how that wouldn't work if it was something like 4- root for example. I think that part could help you
 

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