Help with satellites and planets orbital motion

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SUMMARY

The discussion focuses on calculating the orbital motion of a satellite designed by a Martian civilization. The satellite has a mass of 578 kg and is intended to orbit Mars at an altitude of 602 km. The orbital velocity was calculated using the formula v = √(Gm/r), yielding a result of approximately 3549.92 m/s. The period of the satellite can be determined using the relationship between tangential velocity and orbital radius, while changes in mass and altitude will affect the calculations for velocity and period, but not the fundamental principles governing orbital mechanics.

PREREQUISITES
  • Understanding of Newton's law of universal gravitation
  • Familiarity with orbital mechanics concepts
  • Knowledge of the gravitational constant (G) and mass of Mars (m)
  • Ability to manipulate equations involving velocity and radius
NEXT STEPS
  • Learn how to calculate the orbital period using the formula T = 2πr/v
  • Study the effects of mass on orbital dynamics in satellite motion
  • Explore the implications of changing orbital altitude on satellite velocity
  • Investigate the differences between circular and elliptical orbits
USEFUL FOR

Astronomy students, aerospace engineers, and anyone interested in understanding satellite dynamics and orbital mechanics.

jolynnnicole
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A Martian civilization is attempting to develp the capabilities for space travel. They have built a prototype satellite with a mass of 578kg that they plan to put in orbit Mars a distance of 602km above the surface of mars.

A) Using the data provided, calculate the orbital velocity of the satellite.
B)Find the period of the satellite.
C)How would you answer to (a) change if the satellite was twice as massive? Explain how you know.
D) How would you answer to (a) change if the satellite was to be twice as far from the surface of Mars?


Please explain thoroughly. I really don't understand any of this stuff and need help studying.



The attempt at a solution
I could only do part A and I used the square root of Gm/r which equals
the square root of (6.67E-11)*(6.42E23)/3398km which equals 3398000m and my answer was 3549.921453 m/s

Everything else I'm soooo lost and going to cry bc I don't understand
 
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Knowing the tangential velocity you should find the angular velocity and that should give you the period, for C and D just redo the equations with the new data and describe the change

I guess you don't need to use angular velocity, you could use v = 2∏r/T, where T is the period.
 

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