Help with Stoich limiting reactant Lab

  • #1
Help with Stoich limiting reactant Lab urgent!!

1. I need to find the mass of the excess reactant. This was a lab i did. so its BaCl2.2H20 + Na2So4 --> BaSO4 + 2NaCL. The data i have calculated thus far is.

moles of BaSO4=0.0019 mol
moles of BaCl2=0.0019 mol
moles of Na2SO4=0.0019 mol

mass of BaSo4=.4524g
mass of BaCl2=.4641g
mass of Na2So4= .2698g

Mass of entire salt mixture=1.0038g

The limiting reactant is SO4 and excess is Ba.

BaSo4 is the precipitate.

How do i get the excess reactant!!!
 

Answers and Replies

  • #2
867
0


What are the initial amounts of the reactants? I don't quite understand what the numbers you gave are for.
 
  • #3
Borek
Mentor
28,705
3,194


As Bohrok wrote - you have failed to explain what the question is. What the lab, what you did, what are these numbers. We are not mind readers.

It may came usefull, but we are not.

--
methods
 

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