- #1
gaobo9109
- 69
- 0
Homework Statement
A uniform tube, 60.0cm long, stands vertically with its lower end dipping into water. When the length above water is 14.8cm, and again when it is 48.0cm. the tube resounds to a vibrating fork of frequency 512Hz. Find the lowest frequency to which the tube will resound when it is open at both ends
Homework Equations
The Attempt at a Solution
When the tube is open at both end, the fundamental frequency f1 is given by:
f1=v/(2x0.6)
From the given condition
512 = (2n1-1)v/(4x0.148)
512 = (2n2-1)v/(4x0.48)
How can I find the velocity from the abve two equations?