Help with the Python package Scipy and the Z-transform please

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SUMMARY

The discussion focuses on using the Python package SciPy, specifically the function scipy.signal.lsim2, to simulate signal processing for ultrasound scans. The user seeks assistance in obtaining the Z-transform of a sequence derived from a differential equation related to the processed signal and the signal sent by the probe. The key takeaway is that the Z-transform follows a convolution theorem similar to the Laplace transform, allowing the user to derive the transfer function H_{z} = \frac{U_{sz}}{U_{ez}} by manipulating the equations provided.

PREREQUISITES
  • Understanding of Z-transform and its application in signal processing
  • Familiarity with differential equations and their discrete equivalents
  • Knowledge of the convolution theorem as it applies to transforms
  • Experience with the SciPy library, particularly scipy.signal.lsim2
NEXT STEPS
  • Study the properties of the Z-transform, focusing on the convolution theorem
  • Learn about finite difference methods and their application in signal processing
  • Explore the implementation of scipy.signal.lsim2 for simulating dynamic systems
  • Research the derivation of transfer functions from differential equations
USEFUL FOR

Signal processing engineers, Python developers working with SciPy, and researchers involved in ultrasound technology will benefit from this discussion.

hugo_faurand
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Hello everyone !

I am working on ultrasound scan and the processing of the signal received by the probe. I made the model I wanted and as I do not have an ultrasound scan machine I want to simulate the signal processing.
I will do that with the Python package Scipy and the function [scipy.signal.lsim2] But here is the problem. To use this function I need the Z-transform of a sequence... And I only know few things about Z-transform. I only know a bit about the Laplace Transform and I think I understood that the Z-transform is the discrete version of Laplace transform.
Let me explain what is my problem. Let's say us
is the processed signal and ue
the signal sent by the probe to the computer. I got this differential equation :

$$\frac{du_s(t)}{dt}=−\frac{u_e(t)}{τ}−\frac{u_s(t)}{τ′}$$What I need is the transfer function ##\frac{u_s(t)}{u_e(t)}##

. In the Laplace domain I know I would have :

$$\frac{Us}{Ue}=−\frac{1}{pτ+ττ′}$$I know that to apply the Z-transform I need to consider ue

and us as sequences by sampling them. So now I need to get the Z-transform. I consider the sequences ##(u_{sn})## and ##(u_{en})##. By using the Taylor series (I'm french, I don't know if it's the correct name) the differential equation become : Let's take ##n\in \mathbb{N}##$$ \frac{u_{s(n+1)}−u_{sn}}{T_e}=−\frac{u_{en}}{τ}−\frac{u_{sn}}{τ′}$$But then I don't know what to do to get the sequence equivalent of the transfer function. Could you help me please ? Also, I didn't know how to post this message, I thought that Computer Science section was the better placeThanks in advance.
 
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hugo_faurand said:
But then I don't know what to do to get the sequence equivalent of the transfer function.
The important thing here is that the Z-transform follows a convolution theorem (scroll down in the properties table until you see "convolution"), same as the Laplace transform. You can combine this with the finite difference properties (see "first difference forward" row in the table I mentioned) to generate a transfer function:

$$\frac{u_{s(n+1)} - u_{sn}}{T_e} = -\frac{u_{en}}{\tau} - \frac{u_{sn}}{\tau'}$$
$$\frac{(z-1)U_{sz} - z u_{s}(0)}{T_e} = -\frac{U_{ez}}{\tau} - \frac{U_{sz}}{\tau'}$$
The convolution property means that ##H_{z} = \frac{U_{sz}}{U_{ez}}##, so you just need to solve the above equation for ##H_{z}##. (Edit: ##H_{z}## is the z-transform of the transfer function.)
 
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