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Help with the work done problem!

  1. May 4, 2013 #1
    Hi,

    Some confusion with the attached problem. Some of us say that the work done on the load is W(x+y) while some others are saying that the WD on the load is just Wy since the motor moves the distance x and that work is done by the motor.

    Could we have some clarifications?

    Din
     

    Attached Files:

  2. jcsd
  3. May 4, 2013 #2

    berkeman

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    Staff: Mentor

    Welcome to the PF.

    What are your arguments in favor of each choice?
     
  4. May 4, 2013 #3
    Option (A): One of us argues, since that is the distance the object moves, the WD should be that distance.

    Option (B): The WD here is to bring the load up by a dist of y and multiplied by the force acting on it, which is the weight.

    Force x Dist moved in the direction of the force

    Option (D) : Since the object moves a horizontal distance of x followed by the vertical distance y, thus it W(x+y).
     
  5. May 5, 2013 #4

    SammyS

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    Staff Emeritus
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    Gold Member

    What's the definition of work?

    Do the relative directions of displacement and force matter?
     
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