mycrafish
2n *logn =0.1 *n^2
solve for n
please and thanks!
pozhalste e spaciba!
por favor a obrigadao
solve for n
please and thanks!
pozhalste e spaciba!
por favor a obrigadao
The original poster presents a logarithmic equation involving a variable n, specifically 2n * log(n) = 0.1 * n^2, and seeks assistance in solving for n.
The discussion is ongoing, with participants providing guidance on the need for the original poster to demonstrate their prior efforts. There is no explicit consensus on the approach to take, but there is a focus on clarifying the problem context.
There is an indication that the original poster may have posted the question in multiple locations, which could affect the flow of responses.