Help with this logarithmic equation

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The logarithmic equation 2n * log(n) = 0.1 * n^2 needs to be solved for n. Respondents emphasize the importance of showing prior attempts at solving the equation for effective assistance. The discussion hints at the equation being suitable for a high school level. Users are encouraged to post questions on one board to receive timely responses. Providing context and previous efforts is crucial for obtaining help.
mycrafish
2n *logn =0.1 *n^2

solve for n

please and thanks!
pozhalste e spaciba!
por favor a obrigadao
 
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what level is this? high school?
 
Also, before anyone can "help" you, you need to show what you have tried so we will know what kind of help you need.
 
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Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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