Help with uncertainty calculation

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The discussion centers on calculating the percentage uncertainty in the forced convection heat transfer coefficient using the equation h = 12.5*v^0.6, where v has a value of 5 m/s with a ±0.6 m/s uncertainty. The initial calculation attempted by the user was incorrect, as it relied on an approximation valid only for small percentage errors. Participants suggest using a more precise method for uncertainty calculation rather than the simplified approach. The consensus is that the percentage uncertainty should be calculated using the full formula to achieve accurate results. Accurate calculations are essential for determining the convection heat transfer coefficient's uncertainty.
jim421616
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Homework Statement
An equation for the forced convection heat transfer coefficient over oval shapes is h = 12.5*v^0.6 where v = 5 +/- 0.6 m/s (95% confidence interval). Calculate the percentage uncertainty (95% CI) in the value of the convection heat transfer coefficient, to 1 d.p.
Relevant Equations
h = 12.5*v^0.6
This is from an online quiz. I thought the answer would be
0.6/5 = 0.12
0.12*0.6 = 0.072
∴ 7.2%

but apparently this is wrong. Can anyone help me out please?
 
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jim421616 said:
Homework Statement:: An equation for the forced convection heat transfer coefficient over oval shapes is h = 12.5*v^0.6 where v = 5 +/- 0.6 m/s (95% confidence interval). Calculate the percentage uncertainty (95% CI) in the value of the convection heat transfer coefficient, to 1 d.p.
Relevant Equations:: h = 12.5*v^0.6

This is from an online quiz. I thought the answer would be
0.6/5 = 0.12
0.12*0.6 = 0.072
∴ 7.2%

but apparently this is wrong. Can anyone help me out please?
0.12*0.6 is only an approximation valid for small percentage errors. 12% is rather large. Use the precise formula.
 
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