Help with uncertainty calculation

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SUMMARY

The discussion centers on calculating the percentage uncertainty in the forced convection heat transfer coefficient using the equation h = 12.5*v^0.6, where v = 5 ± 0.6 m/s. The initial calculation of 7.2% was incorrect due to the use of an approximation method that is valid only for small percentage errors. Participants emphasized the need to apply a more precise formula for accurate results, especially given the relatively large percentage error involved.

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jim421616
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Homework Statement
An equation for the forced convection heat transfer coefficient over oval shapes is h = 12.5*v^0.6 where v = 5 +/- 0.6 m/s (95% confidence interval). Calculate the percentage uncertainty (95% CI) in the value of the convection heat transfer coefficient, to 1 d.p.
Relevant Equations
h = 12.5*v^0.6
This is from an online quiz. I thought the answer would be
0.6/5 = 0.12
0.12*0.6 = 0.072
∴ 7.2%

but apparently this is wrong. Can anyone help me out please?
 
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jim421616 said:
Homework Statement:: An equation for the forced convection heat transfer coefficient over oval shapes is h = 12.5*v^0.6 where v = 5 +/- 0.6 m/s (95% confidence interval). Calculate the percentage uncertainty (95% CI) in the value of the convection heat transfer coefficient, to 1 d.p.
Relevant Equations:: h = 12.5*v^0.6

This is from an online quiz. I thought the answer would be
0.6/5 = 0.12
0.12*0.6 = 0.072
∴ 7.2%

but apparently this is wrong. Can anyone help me out please?
0.12*0.6 is only an approximation valid for small percentage errors. 12% is rather large. Use the precise formula.
 

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