HelpHow functions are driven from graphs?

  • Context: Undergrad 
  • Thread starter Thread starter gholamghar
  • Start date Start date
  • Tags Tags
    Functions Graphs
Click For Summary

Discussion Overview

The discussion centers on the methods for deriving equations from graphs, specifically in the context of open channel flows and the relationship between specific energy and height. Participants explore various mathematical approaches and interpretations of the graph presented.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions how the equation E=y+(q^2)/2*g*y^2 is derived from the graph, noting discrepancies with a trendline equation obtained from Excel.
  • Another participant corrects the terminology used, emphasizing that the graph cannot represent a parabola based on its described features and suggests it may be a hyperbola.
  • A later reply clarifies the equation format, indicating that the original equation was misread and provides a corrected interpretation.
  • One participant proposes a general equation ax=ay+(b/y^k) to describe the graph's behavior, suggesting specific values for constants based on the graph's characteristics.
  • Participants express interest in finding reference materials that contain various graphs and their corresponding equations, indicating a desire for further resources on the topic.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct interpretation of the graph or the derivation of the equations. Multiple competing views and interpretations remain present throughout the discussion.

Contextual Notes

There are unresolved assumptions regarding the graph's characteristics and the specific forms of the equations being discussed. The discussion also reflects a dependence on the definitions of terms and the mathematical structures involved.

gholamghar
Messages
23
Reaction score
0
Hello
my question is how and with which methods Equations are derived from graphs,for example the graph below is for specific energy in open channel flows,and the equation to it is :
E=y+(q^2)/2*g*y^2

how this equation has been obtained from the graph?
if in Excel you add a trendline to this figure and then you find the equation with Excel,the best it gives you is this:y = -0.0453*E^2 + 1.6595*E - 2.3539
and this is totally different with the above equation,
so how do they obtain equations from the graphs?
thanks
 

Attachments

  • untitled1.JPG
    untitled1.JPG
    6.4 KB · Views: 406
Last edited:
Mathematics news on Phys.org
First, the word is "derived", not "driven" or "drove"- that's a whole different thing!

Second, the graph you show can't possibly be of the form "E=y+(q^2)/2*g*y^2". That gives a parabola with horizontal axis and this doesn't have a horizontal axis. Also if those two lines are asymptotes, the graph is not a parabola, although it can be a hyperbola. Assuming that the graph is a hyperbola with asymptotes y= x and y= 0, and center at (0,0), then we can rotate the graph clockwise by \pi/8 radians so that the axes are the E-axis and the y-axis. Now the asymptotes are y= tan(\pi/8)E) and y= -tan(\pi/8)E)[/itex] and the equation is
tan^2(\pi/8)E^2- y^2= A
for some positive number A. You can determine A by the requirement that Emin, yc satisfy that equation.
 
thank you for reply,i think you have read the equation i wrote in a wrong way,now i rewrite it:
E=(y)+(q^2)/(2*g*(y^2))
g=9.8 m/s^2
q=constant
y=height
E=energy
so it is not a parabola.
but is there any reference book that has different graphs and their equations?
i have a post here:
https://www.physicsforums.com/showthread.php?t=325862

i need to find the equation for the graph in that post,the graph is like two continuous Cosine digrams but with different amplitudes,is there any reference for these kind of problems?
thanks again
 
Last edited:
You are right- I did not see that the "y^2" is in the denominator.
 
gholamghar said:
Hello
my question is how and with which methods Equations are derived from graphs

Since this graph isn't pretty conventional and nothing too absurd, you need to look at its features and simply use logic to solve them.
Since the graph has asymptotes of y=x and y=0, this means that as y \rightarrow \infty then x \rightarrow y,0

Such an equation that will accomplish this task is:

x=y+\frac{1}{y}

notice how in the RHS, the fraction is what changes the entire structure of the graph. As y \rightarrow \infty then \frac{1}{y} \rightarrow 0 so the graph tends towards y=x but as y\rightarrow 0 then \frac{1}{y} \rightarrow \infty so now the graph tends towards y=0

but we need a general equation for this, and basically that would be:

ax=ay+\frac{b}{y^k} for some constants a,b,k

for your graph, it is already given that a=1, b=\frac{q^2}{2g} and k=2
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 37 ·
2
Replies
37
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K