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GGalaxy

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**Please correct me if I am wrong in anything below, including clauses.**

i was trying to find a simple explanation for the frequency and i come up with this ,

1)

Frequency (Hertz(or s^-1)) = 1/ T (Seconds)

F = 1/T => T (seconds) = 1/ F(s^-1)

2)

"Place A" is 338 Kilometers away from "Place B", imagine if you say something out-lowed (yelling) in a pipe , let's say for example "Hello" and we channel a pipe between "A" and "B" and i wait for your Hello to be listened , knowing that the human voice's frequency ranges in 75–150 Hz for men and 150–300 Hz for women, so let's say, you have 150 Hz,in how many minutes, I'm going to receive your Hello?

**- Solution :**

The smaller the period, the higher the frequency and the bigger the period, the lower the frequency, meaning the more you yell the more the frequency reduces => it will last longer.?

F=1/T => T = 1/F, and Lambda = Velocity / Frequency,

Lambda = wavelength

Velocity = the speed (the way we are going to travel your hello to me, i am going to use the speed of sound in air = 340 meter/sec)

Frequency = 150 Hz

Application :

340 meter ===> 1 sec

338 000 meter ==> x sec

==> x (sec) = 338 000 / 340 = 995 sec = 17 minutes , so it will take 17 minutes for me to hear your Hello, and that if i use the sound speed, if i use the light speed its going to be in just few seconds.

AND I DON'T REALLY UNDERSTAND WHAT FREQUENCY IS REALLY MEAN, PLEASE GIVE A SHORT EXAMPLE,

**i mean i understand how to calculate, but i don't understand what it is i am calculating**Thank You guys

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