What Is the Final Speed After Two Hockey Players Collide?

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SUMMARY

The final speed after two hockey players, each weighing 72.0 kg and skating at 5.45 m/s, collide and stick together at an angle of 115 degrees is calculated to be 2.93 m/s. The momentum conservation equations used include p = mv and p_{i} = p_{f}. The initial momentum components were adjusted using the sine function for the angle of 57.5 degrees, leading to the correct calculation of the final velocity.

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Homework Statement


Two 72.0 kg hockey players skating at 5.45 m/s collide and stick together. If the angle between their initial directions was 115^{o}, what is their speed after the collision?


Homework Equations


p = mv

p_{i} = p_{f}


The Attempt at a Solution



Here's my interpretation of the image;

http://img696.imageshack.us/img696/1493/momentum.png

p_{ix} = p_{fx} = 0

p_{iy} = p_{fy}

m_{A}v_{A} + m_{B}v_{B} = (m_{AB})(v_{AB})

(72)(5.45cos(32.5)) + (72)(5.45cos(32.5)) = 144v_{AB}

v_{AB} = 4.60 m/s

Am I correct?
 
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P*cosθ components of the two players get canceled according to the diagram given by you . Check the other components. Your calculation will be correct if you use θ = 57.5 degrees.
 
rl.bhat said:
P*cosθ components of the two players get canceled according to the diagram given by you . Check the other components. Your calculation will be correct if you use θ = 57.5 degrees.

Oh, so I need to use sin instead?
 
Precursor said:
Oh, so I need to use sin instead?
For your mentioned angle, yes.
 
Ok, so the new answer is 2.93 m/s.

Thanks for the help
 

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