Ice skaters collision with angle

Click For Summary

Homework Help Overview

The problem involves two ice skaters colliding at angles, with one skater's mass and velocity given, and the other skater's mass and velocity also specified. The task is to determine the velocity of one skater after the collision and to assess the conservation of kinetic energy.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss how to incorporate angles into momentum equations and the process of breaking down velocities into components. There are questions about calculating final velocities based on given angles and magnitudes.

Discussion Status

Participants are actively engaging with the problem, confirming methods for calculating components of velocity and discussing the need for both magnitude and direction in the final answer. There is a collaborative atmosphere with some members providing affirmations of others' reasoning.

Contextual Notes

There is an emphasis on understanding vector components and the need to calculate both magnitude and angle for the final velocity. The discussion reflects a focus on ensuring clarity in the application of physics principles without providing direct solutions.

fantisism
Messages
16
Reaction score
0

Homework Statement


Two ice skaters crash into each other. Before they collide, one of them (50 kg) is skating in a straight line at 5 m/s, the other (40 kg) is skating at 4 m/s in a straight line at 90 degrees to the 50 kg skater’s direction. After the collision, the 50 kg skater is moving at 4 m/s at an angle of 25 degrees relative to their original direction. Calculate the velocity of the 40 kg skater after the collision. Is the total kinetic energy constant?

Homework Equations


m1v1ix+m2v2ix=m1v1fx+m2v2fx
m1v1iy+m2v2iy=m1v1fy+m2v2fy

The Attempt at a Solution


I drew a diagram before collision and after collision. Really, all I need to know is where in the formula(s) would I need to include the angle and I SHOULD be able to figure it out from there.
FullSizeRender.jpg
 
Physics news on Phys.org
You have v1fx and v1fy in the equations for components of momentum. How do you get them, knowing magnitude and angle of velocity ?
 
ehild said:
You have v1fx and v1fy in the equations for components of momentum. How do you get them, knowing magnitude and angle of velocity ?
Is v1fx=(4 m/s)(cos(25°)) and v1fy=(4 m/s)(sin(25°))?
 
fantisism said:
Is v1fx=(4 m/s)(cos(25°)) and v1fy=(4 m/s)(sin(25°))?
Yes.
 
ehild said:
Yes.
And then with that information, solve for v2fx and v2fy?
 
fantisism said:
And then with that information, solve for v2fx and v2fy?
Yes.
 
ehild said:
Yes.
And then once I figure out what those two velocities are, I would square them individually and take the square root of the sums? So, sqrt((v2fx)2+(v2fy)2? And that would be the answer for the first question?
 
fantisism said:
And then once I figure out what those two velocities are, I would square them individually and take the square root of the sums? So, sqrt((v2fx)2+(v2fy)2? And that would be the answer for the first question?
The final velocity is asked. It is a vector with magnitude and direction. I think the problem wants both the magnitude and angle.
 
ehild said:
The final velocity is asked. It is a vector with magnitude and direction. I think the problem wants both the magnitude and angle.
To find the angle, would it be arctan(v2fy/v2fx)?
 
  • #10
fantisism said:
To find the angle, would it be arctan(v2fy/v2fx)?
Yes.
 
  • #11
Alright. I can solve the second subquestion myself. Thank you again!
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 19 ·
Replies
19
Views
7K
  • · Replies 14 ·
Replies
14
Views
3K
Replies
3
Views
2K
  • · Replies 20 ·
Replies
20
Views
13K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 3 ·
Replies
3
Views
5K