Hollow and solid cylinder, going down a slope

[wavingerwin]

Homework Statement

Well, I thought of the question myself:
There are two identical straight slopes, 30⁰ to the horizontal and 10m long at their hypotenuse. Each of them has one cylinder of identical shape of r=1m and mass (1kg) respectively. However, one is solid whereas the other is hollow.
They are attracted downwards by the same gravity force (10N, suppose gravitational accerleration is 10ms^-2), and as a result of the support
force perpendicular to the slope's surface, an identical pull force parallel to the surface is pulling each cylinder (5N, derived from: sin30⁰=F/F_g).
Deduce the time taken for each cylinder to reach the bottom of the slopes!
(Of course, the hollow will take a longer time because it has a greater rotational inertia due to its mass concentrated on further distance compared to the solid cylinder, hence angular acceleration is bigger)

Homework Equations

Rotational inertia of hollow cylinder = mr²
Rotational inertia of solid cylinder = mr²/2
Torque = Rotational inertia*angular acceleration
Torque = force*perpendicular distance
linear acceleration = angular acceleration*radius
linear distance = initial linear speed*time taken + linear acceleration*time taken²/2
(initial linear speed = 0)

3. The attempt at the solution
When i tried to solve this question, i cannot do it without calculating or assuming friction force between the cylinders and the slope's surface. (Hence, the force of 5N which pulls the cylinders is not needed).

Suppose, the friction is 1N, hence torque is 1Nm.
Angular acceleration of the solid cylinder is Torque/rotational inertia = 1/0.5 = 2radians/s
Angular acceleration of the hollow cylinder is Torque/rotational inertia = 1/1 = 1radians/s

Linear acceleration of the solid cylinder = 2ms^-2
Linear acceleration of the hollow cylinder = 1ms^-2

hence using the last equation and rearrangements, time taken for solid cylinder is 10^1/2s
and time taken for hollow cylinder is 20^1/2s

Am i right?
can the problem be solved without assuming/calculating friction?

Thank You!

 

[TMFKAN64]

If you don't have friction, you don't have any rotation... only the friction force applies a torque to your cylinder!

If you specify that the friction force is sufficient so that the motion is purely rotational (no slippage), I think you can solve the problem using conservation of energy.