Homework Help: Calculating Moment of Inertia & Radius of Gyration

Click For Summary

Homework Help Overview

The discussion revolves around calculating the moment of inertia and the radius of gyration in a physics context, specifically related to rotational motion and dynamics. Participants explore the relationships between mass, distance, and acceleration in the context of a physical system.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the calculation of moments about different points, questioning how to account for various distances and accelerations. There is an exploration of the relationship between linear and angular motion, particularly how to express Newton's second law in a rotational context.

Discussion Status

Some participants have provided affirmations of the calculations presented, while others raise further questions about the relationships between tangential acceleration, angular acceleration, and moments. The discussion appears to be productive, with participants engaging in a back-and-forth to clarify concepts and calculations.

Contextual Notes

There are indications of uncertainty regarding the application of the parallel axis theorem and the specifics of how to incorporate distance and mass into the calculations. Participants are also navigating the implications of given values such as tangential acceleration and radius.

lupinpooter
Messages
5
Reaction score
0

Homework Statement



3KMRh.jpg

eFqdu.jpg

Oiq2y.jpg


Homework Equations



radius of gyration:
r = root (I/m)
I = moment of inertia
m = mass

parallel axis theorem given above

The Attempt at a Solution



Okay, so I think the moment about CM is just m*0.24^2, but after that, I'm less sure.
Is the moment about the hip just m*0.42^2 + m*0.24^2?

If so, it's taking the acceleration and the distance to the toe into account that I'm having difficulty with. Is it just F = ma? If so, is the m taken from the moment of inertia at the hip, or the toe? I figure the distance to the toe must be significant, but I don't know how to account for it.

Any help?
 
Physics news on Phys.org
lupinpooter said:
Okay, so I think the moment about CM is just m*0.24^2, but after that, I'm less sure.
Is the moment about the hip just m*0.42^2 + m*0.24^2?
Yes, you've got it.

If so, it's taking the acceleration and the distance to the toe into account that I'm having difficulty with. Is it just F = ma? If so, is the m taken from the moment of inertia at the hip, or the toe?
How would you write the equivalent of F = ma for rotational motion?
I figure the distance to the toe must be significant, but I don't know how to account for it.
Given the tangential acceleration, how would you find the angular acceleration?
 
Doc Al said:
Yes, you've got it.


How would you write the equivalent of F = ma for rotational motion?

Given the tangential acceleration, how would you find the angular acceleration?

Okay, maybe it's best to do the last two bits in reverse order;
if the tangential acceleration is 18m/s^2, and the radius is 1m, is the angular acceleration also 18 radians/s^2?

Then is the moment: angular acceleration * the moment about the hip?
And that's the final answer?
 
lupinpooter said:
Okay, maybe it's best to do the last two bits in reverse order;
if the tangential acceleration is 18m/s^2, and the radius is 1m, is the angular acceleration also 18 radians/s^2?
Right!

Then is the moment: angular acceleration * the moment about the hip?
And that's the final answer?
Right again.
 
Awesome,
thanks man, I really appreciate it.
 

Similar threads

Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
6K
  • · Replies 11 ·
Replies
11
Views
1K
Replies
11
Views
4K
  • · Replies 28 ·
Replies
28
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K