Homework help or pointers anyone?

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The discussion revolves around calculating the height of the final image formed by a system of lenses, specifically a converging lens with a focal length of 20.4 cm and a diverging lens with a focal length of -42.4 cm. The object is positioned 31.1 cm to the left of the converging lens. A critical mistake identified was the misapplication of sign conventions in optics, emphasizing the importance of accurate diagramming to visualize image formation. The correct application of these principles is essential for solving lens-related problems effectively.

PREREQUISITES
  • Understanding of lens formulas and image formation
  • Familiarity with sign conventions in optics
  • Basic knowledge of converging and diverging lenses
  • Ability to interpret and draw ray diagrams
NEXT STEPS
  • Study the lens formula: 1/f = 1/do + 1/di
  • Learn about ray tracing techniques for lens systems
  • Explore the effects of multiple lenses on image formation
  • Review sign conventions in optics for both converging and diverging lenses
USEFUL FOR

Students studying optics, physics educators, and anyone seeking to understand the principles of image formation using lens systems.

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homework help or pointers anyone?

A 1.29-cm-tall object is placed 31.1 cm to the left of a converging lens with a focal length f1 = 20.4 cm. A diverging lens, with a focal length f2 = -42.4 cm, is placed 31.1 cm to the right of the first lens. How tall is the final image of the object?


im not quite artistic enough to draw this picture for you sorry but any help or direction ect is appreciated
 
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got it

never mind! sorry i was stupid and missed a sign...had a positive in a number i should have had a negative
 
Sign conventionas are always a problem in optics, it is useful to always draw a rough diagram and have a feel for where the image should be for an object in front and behind the focal poitn for a concave and convex lens.
 

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