Orbital angular momentum and kinetic energy

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Homework Statement



Please see attached.

I have two questions:

how does pr get to be -ihbar (D/Dr + 1/r) ? where does the extra factor of D/Dr come from? one comes from r.del, but what about the other? surely div (r/r) = 2/r?

Also, why does [r,pr]=-ih[r,D/Dr] = ih?

surely -ih[r,D/Dr] = -ih(rD/Dr - 1)?

am i missing something?

Homework Equations





The Attempt at a Solution



See my attempt above. thanks!
 
Attachments
  • Printed textbook page, rotated sideways, showing equations 7.62 to 7.68 on the radial momentum operator p_r, including p_r = -(ih/2)(r-hat dot del) and the derivation of p_r = -ih(d/dr + 1/r) and the commutator [r, p_r] = ih.
    question..jpg
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To calculate [r, d/dr], you need to use the product rule in calculating the second term:

[tex]\left[r,\frac{\partial}{\partial r}\right]\psi = r\left(\frac{\partial}{\partial r}\psi\right) - \frac{\partial}{\partial r}(r\psi) = r\left(\frac{\partial}{\partial r}\psi\right) - \left[\left(\frac{\partial}{\partial r}r\right)\psi + r\left(\frac{\partial}{\partial r}\psi\right)\right] = -\psi[/tex]
 
Great thanks!

any ideas on the previous bit of my question?

Thanks!
 
Probably a similar reason. Try working it out again.