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mandy9008
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Homework Statement
When a 2.90-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 2.93 cm.
(a) What is the force constant of the spring?
(b) If the 2.90-kg object is removed, how far will the spring stretch if a 1.45-kg block is hung on it?
Homework Equations
Hooke's law: Fs=-kx
F=ma
The Attempt at a Solution
a. F=ma
F= (2.90 kg) (9.8 m/s2)
F=28.42N
Fs=-kx
27.42 N=-k (0.0293m)
k=970.0 N/m
b. F=ma
F= (1.45 kg) (9.8 m/s2)
F=14.21 N
Fs=-kx
14.21 N = (970 N/m) x
x=0.015 cm