Hooke's Law- measurement of mass/weight

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SUMMARY

The discussion focuses on applying Hooke's Law to determine the mass and weight of an unknown body hanging from a spring. The spring constant is given as 104 N/cm, and the spring stretches 50 cm. The correct equations used are Mg = k/ΔL for weight and W = Mg for mass. The final calculations yield a weight of 5200 N and a mass of approximately 530.6 kg.

PREREQUISITES
  • Understanding of Hooke's Law and its application in physics
  • Familiarity with the concepts of mass and weight
  • Basic algebra for rearranging equations
  • Knowledge of gravitational acceleration (g = 9.8 m/s²)
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  • Study the derivation and applications of Hooke's Law in different contexts
  • Learn about the relationship between force, mass, and acceleration
  • Explore the concept of spring constants and their significance in mechanics
  • Investigate the effects of varying spring constants on mass measurements
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of mechanics and the practical applications of Hooke's Law.

thennathalie
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A body of unknown mass hangs from a spring and stretches it to 50 cm. If the spring constant is 104 N/cm determine:

a. the weight of the body
b. the mass of the body


k = mg/∆L
W= Mg


mass : k = mg/∆L 50/104= .4807692308
weight : W= Mg .4807692308*9.8=4.711538462
 
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thennathalie said:
A body of unknown mass hangs from a spring and stretches it to 50 cm. If the spring constant is 104 N/cm determine:

a. the weight of the body
b. the mass of the body


k = mg/∆L
W= Mg


mass : k = mg/∆L 50/104= .4807692308
weight : W= Mg .4807692308*9.8=4.711538462

In your attempt to find the mass you've calculated ΔL/k, which is not correct. Your Relevant Equation says k = Mg/ΔL. Rearrange that equation to solve for M. Note that there's a g in there!

Since Mg is the weight and Mg appears in your first Relevant Equation, you can find the weight first by rearranging the equation to place Mg on the left.
 
Hi, and welcome to the Physics Forums.

What are the units of your answers. Have you substituted your answers back into the formulae as a check of their validity?
 
Okay, so what you're telling me is that the equation will be Mg= k/∆L
and not k=Mg/∆L/.

using the new equation:

Mg= k/∆L
Mg= 104/50 which gives me 2.08
Mg= 2.08

so the weight would be 2.08?
 
My unit for weight is N.
And for Mass is Kg.

I have not, didn't think about that. Thanks
 
thennathalie said:
Okay, so what you're telling me is that the equation will be Mg= k/∆L
and not k=Mg/∆L/.

using the new equation:

Mg= k/∆L
Mg= 104/50 which gives me 2.08
Mg= 2.08

so the weight would be 2.08?

Ahhh. Nope :shy:

Hooks law is usually presented as (ignoring the sign implying the direction of the force):

F = k ΔL

Where F is the force applied to the spring, ΔL the change in its length.

In your case the force is a weight due to gravity, Mg, so that Mg = k ΔL

Your Relevant Equation said:

k = Mg/ΔL

This is just an algebraic rearrangement of the same formula. You need to be able to perform these manipulations of the formulas in order to be able to solve for whatever unknown values are buried in the formula
 
Thanks for keeping up with me.
I am new to physics.

That means i would have to multiply 104*50 = 5200?
 
thennathalie said:
Thanks for keeping up with me.
I am new to physics.

That means i would have to multiply 104*50 = 5200?

Yes, that's what the formula says. What are the units?
 
Would be 5200 N because is weight.

So for the mass,

I would use the W=Mg formula.

5200=m9.8
M=530.6kg
 
  • #10
thennathalie said:
Would be 5200 N because is weight.

So for the mass,

I would use the W=Mg formula.

5200=m9.8
M=530.6kg

Yup. Looks good. :smile:
 
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  • #11
☺️ thank you so much.
 

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