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CAG0625

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## Homework Statement

A 0.20 kg mass hangs vertically from a spring and an elongation below the support point of the spring of 9.50 cm is recorded. With 1.00 kg hanging on the spring, a second elongation of 12.00 cm is recorded. Calculate the spring constant k in Newtons per meter. (Note the equilibrium position is not 0.) Then at the elongation of 9.50 cm, a frequency of 300 rev/min is recorded. Then at elongation of 12.00 cm, frequency of 400 rev/min is recorded. Calculate the effective mass of the system in kilograms. (convert to SI. w=f*2pi/60 switches from rev/min to rad/sec.)

## Homework Equations

W=mg

W=-kd

## The Attempt at a Solution

W=(0.20kg)(980.35 cm/s^2) = 196.07N

W=(1.00kg)(980.35cm/s^2)=980.35N

196.07N=-k(0.095m)=-2063.89N/m

980.35N=-k(0.12m) = -8169N/m

Is that all correct and I do not know where to go from here.