Hooke's Law- measurement of mass/weight

AI Thread Summary
A body of unknown mass stretches a spring by 50 cm with a spring constant of 104 N/cm. The correct approach to find the weight is to use the formula Mg = kΔL, resulting in a weight of 5200 N. Subsequently, using the weight in the equation W = Mg, the mass is calculated to be approximately 530.6 kg. The discussion emphasizes the importance of correctly manipulating formulas in physics to solve for unknowns. Understanding these principles is crucial for accurate measurements in experiments involving Hooke's Law.
thennathalie
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A body of unknown mass hangs from a spring and stretches it to 50 cm. If the spring constant is 104 N/cm determine:

a. the weight of the body
b. the mass of the body


k = mg/∆L
W= Mg


mass : k = mg/∆L 50/104= .4807692308
weight : W= Mg .4807692308*9.8=4.711538462
 
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thennathalie said:
A body of unknown mass hangs from a spring and stretches it to 50 cm. If the spring constant is 104 N/cm determine:

a. the weight of the body
b. the mass of the body


k = mg/∆L
W= Mg


mass : k = mg/∆L 50/104= .4807692308
weight : W= Mg .4807692308*9.8=4.711538462

In your attempt to find the mass you've calculated ΔL/k, which is not correct. Your Relevant Equation says k = Mg/ΔL. Rearrange that equation to solve for M. Note that there's a g in there!

Since Mg is the weight and Mg appears in your first Relevant Equation, you can find the weight first by rearranging the equation to place Mg on the left.
 
Hi, and welcome to the Physics Forums.

What are the units of your answers. Have you substituted your answers back into the formulae as a check of their validity?
 
Okay, so what you're telling me is that the equation will be Mg= k/∆L
and not k=Mg/∆L/.

using the new equation:

Mg= k/∆L
Mg= 104/50 which gives me 2.08
Mg= 2.08

so the weight would be 2.08?
 
My unit for weight is N.
And for Mass is Kg.

I have not, didn't think about that. Thanks
 
thennathalie said:
Okay, so what you're telling me is that the equation will be Mg= k/∆L
and not k=Mg/∆L/.

using the new equation:

Mg= k/∆L
Mg= 104/50 which gives me 2.08
Mg= 2.08

so the weight would be 2.08?

Ahhh. Nope :shy:

Hooks law is usually presented as (ignoring the sign implying the direction of the force):

F = k ΔL

Where F is the force applied to the spring, ΔL the change in its length.

In your case the force is a weight due to gravity, Mg, so that Mg = k ΔL

Your Relevant Equation said:

k = Mg/ΔL

This is just an algebraic rearrangement of the same formula. You need to be able to perform these manipulations of the formulas in order to be able to solve for whatever unknown values are buried in the formula
 
Thanks for keeping up with me.
I am new to physics.

That means i would have to multiply 104*50 = 5200?
 
thennathalie said:
Thanks for keeping up with me.
I am new to physics.

That means i would have to multiply 104*50 = 5200?

Yes, that's what the formula says. What are the units?
 
Would be 5200 N because is weight.

So for the mass,

I would use the W=Mg formula.

5200=m9.8
M=530.6kg
 
  • #10
thennathalie said:
Would be 5200 N because is weight.

So for the mass,

I would use the W=Mg formula.

5200=m9.8
M=530.6kg

Yup. Looks good. :smile:
 
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  • #11
☺️ thank you so much.
 
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