A baseball hit at an angle of(adsbygoogle = window.adsbygoogle || []).push({}); ato the horizontal with initial velocity v_{0}has horizontal range, R, given by

R = (v_{0}^{2}/ g)sin(2a)

Here g is the acceleration due to gravity. Sketch R as a function ofafor 0 <a< pi/2. What angle gives the maximum range? What is the maximum range?

For the graph, would I just graph a sin curve where the maxes are at v_{0}^{2}/g and the mins are at -v_{0}^{2}/g... And of course I'd keep the domain restricted as the question said. Then it would have a period of pi as well, and that would be enough info to graph it out right?

As for the angle that gives the maximum range, I'd probably have to use the graph and divide one oscillation into parts to see where in that interval the maximum was reached.

And, for the last question, I guess the maximum would be v_{0}^{2}/g?

Just tell me if my reasoning is correct.

Thanks

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# Homework Help: Horizontal path of a baseball as a sine function

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