A 3kg block is resting at the bottom of a ramp that is at a 37 degree angle with a coefficient of friction of .2. A spring at the bottom of the hill has a spring constant of 5000N/m. The block compresses the spring 8cm (so .08m) and is then released. The block slides up the ramp and then slides back down the ramp. a. Find the velocity of the block as it starts to slide up the ramp. I did this problem, and my teacher said it was right. V = 3.26m/s b. Find the velocity of the block when it returns to the bottom of the ramp on the way back down. I got 3.38 m/s, is this right? Ff =16*2=3.2N 16-3.2=12.8 12.8=28l l=.711 WFf=Fd W=(3.2)(.711)=2.21(2)=4.55 16-4.55=11.45J KE=1/2m^2 11.45=.5(2)v^2 v=3.38 m/2 c. Find the amount that the block will compress the spring when it comes back down. Is it asking how many joules or how many meters? I got .067m, is this right? 11.45=.5(5000)x^2 11.45=2500x^2 .00458=x^2 x=.067m Note: This isn't homework. It's not a grade of any sort. I'm doing some practice problems from old worksheets to prepare for a test tomorrow. So I'm trying to understand how to do it, the concepts of it, not just what these answers are. I could care less.