Block moves down incline, hits spring, find spring constant

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Homework Help Overview

The problem involves a block sliding down an incline and compressing a spring. The context includes energy conservation principles, specifically relating gravitational potential energy and spring potential energy.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to relate the energies involved in the system and questions whether gravitational potential energy should be included when the block comes to rest at maximum compression of the spring. Some participants seek clarification on whether the given compression is the maximum point or just a momentary rest position.

Discussion Status

Participants are exploring the assumptions regarding the energy states of the block and spring system. There is a mix of agreement and clarification requests, indicating a productive dialogue about the interpretation of the problem's conditions.

Contextual Notes

There is uncertainty regarding the definition of Δx in the context of the problem, specifically whether it represents the maximum compression of the spring or a point where the block is momentarily at rest.

jybe
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Homework Statement


[/B]
The block, initially at rest, slides down the ramp and compresses the spring 0.03 m.

Theta = 30 degrees
L = 1.25 m
M of block = 2 kg
Δx = 0.03 m

1) Write the expression for the initial and final energy states

2) Find the spring constant K

Homework Equations



mgh = 0.5kx2

The Attempt at a Solution



Can I say that when the block compresses the spring and comes to rest, h=0, in which case I wouldn't have to include mgh on the right hand side of the energy equation?

mg(L*sin theta) = 0.5*k*(x2) and solve for k...

This seems too easy, am I approaching this wrong?
 

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Looks good to me!
 
I would clarify. Is it saying it comes to rest at Δx, or is it saying that Δx is the maximum compression (more likely scenario)? What do you expect is going to happen from your real life experiences?

It appears you are saying, it "just" is at rest there (before it recoils), so kinetic energy is zero right at that point.
 
scottdave said:
Is it saying it comes to rest at Δx, or is it saying that Δx is the maximum compression (more likely scenario)?
While it never hurts to ask for clarification, the point of max compression is when it comes to rest (momentarily). That's what I assumed was being described.
 
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