Maximum speed of a box compressing a spring on an inclined p

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Homework Help Overview

The problem involves a box sliding down a frictionless ramp and compressing a spring, with the goal of determining the maximum speed of the box after it compresses the spring. The subject area includes mechanics, specifically energy conservation and dynamics on an incline.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of force considerations versus energy methods in analyzing the problem. There is confusion regarding the application of potential energy and how it relates to the maximum speed of the box.

Discussion Status

The discussion is ongoing, with participants questioning the reasoning behind the methods used and expressing confusion about the relationship between potential energy and the maximum speed. Some guidance has been offered regarding the relevance of different pieces of information in the problem.

Contextual Notes

Participants note the potential oversight of not using the potential energy formula and question whether all provided information is necessary for solving the problem. There is also a suggestion to clarify the problem statement to ensure all aspects are considered.

harik2000
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Homework Statement



A box of mass m = 40kg is released from rest at thte top of a frictionless ramp. The ramp makes an angle theta = 45 degrees to the horizontal. After sliding fom the rigin a distance d = 2.00 m down the ramp, the box strikes a spring of force constant k = 500 N/m. The box compresses the spring momentarily stops, and then begins to slide back up the ramp. What is the maximum speed of the box?

Homework Equations

The Attempt at a Solution


mgsin(45) = kx
(9.81 * 40)sin45 = 500x
x= 0.5547

1/2(k)(x^2) = 1/2(m)(v^2)
v = 1.96m/s

Can anyone verify this pls?
 
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harik2000 said:
mgsin(45) = kx
(9.81 * 40)sin45 = 500x
x= 0.5547

1/2(k)(x^2) = 1/2(m)(v^2)
v = 1.96m/s

Can anyone verify this pls?

It doesn't look right to me. Any reason why you used force considerations to do the first part, and energy do do the latter part?
 
Mister T said:
It doesn't look right to me. Any reason why you used force considerations to do the first part, and energy do do the latter part?

I was trying to find the displacement provided when the ball compresses the spring the most however realized that I did not use potential energy mgh and I was confused. Can you show me the steps? I am confused.
 
harik2000 said:
I was trying to find the displacement provided when the ball compresses the spring the most however realized that I did not use potential energy mgh and I was confused. Can you show me the steps? I am confused.

What part confuses you?
 
I am confused about the potential energy so it would be equal to mgh = 1/2 k x^2 but how would that help solve for v?
 
harik2000 said:
I am confused about the potential energy so it would be equal to mgh = 1/2 k x^2 but how would that help solve for v?

Solve it for x and tell us what you get.
 
harik2000 said:
I am confused about the potential energy so it would be equal to mgh = 1/2 k x^2 but how would that help solve for v?
It won't.
First, please check you have stated the problem exactly.
Is it the whole problem or are there more parts? If there are more parts (and even if there aren't) consider the possibility that not all the information is relevant to finding the max speed.
Then consider at what point in the whole process you would expect max speed to be reached.
 

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