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A trolley of mass 930 g is held on a horizontal surface by means of two springs,one spring on the left and right respectively.The variation with time t of the speed v of the trolley for the first 0.60s of its motion is shown in the fig(It's a v-t graph,max y=8.0cms^-1 ,min x=0.0s & 0.6s) below.

Use the fig above to determine the distance moved during the first 0.60s of its motion.

The answer=0.031m +-.001m.I find using a triangle to find half of the distance,then multiply 2 to get the whole distance not satisfying.I used s=ut +at^2/2 also and still didn't get it.Any 1 pls tell of a way to get the ans?

*Edit

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# Homework Help: How 2 find distance from non uniform velocity time graph where can't use triangle?

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