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How 2 find distance from non uniform velocity time graph where can't use triangle?

  1. Feb 22, 2007 #1

    inv

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    Hi. *Problem solved.

    A trolley of mass 930 g is held on a horizontal surface by means of two springs,one spring on the left and right respectively.The variation with time t of the speed v of the trolley for the first 0.60s of its motion is shown in the fig(It's a v-t graph,max y=8.0cms^-1 ,min x=0.0s & 0.6s) below.

    [​IMG]

    Use the fig above to determine the distance moved during the first 0.60s of its motion.

    The answer=0.031m +-.001m.I find using a triangle to find half of the distance,then multiply 2 to get the whole distance not satisfying.I used s=ut +at^2/2 also and still didn't get it.Any 1 pls tell of a way to get the ans?


    *Edit
     
    Last edited: Feb 23, 2007
  2. jcsd
  3. Feb 22, 2007 #2

    inv

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    *Double post,from merge of 2 posts,sry.
     
    Last edited: Feb 23, 2007
  4. Feb 22, 2007 #3
    What is the area under the curve?
     
  5. Feb 22, 2007 #4
    What is the area under the curve?
     
  6. Feb 22, 2007 #5
    Im sorry, but I dont understand what your talking about. Its not 'area', it represents something.
     
    Last edited: Feb 22, 2007
  7. Feb 22, 2007 #6
    Im sorry, but I dont understand what your talking about. Its not 'area', it represents something.
     
  8. Feb 22, 2007 #7

    inv

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    It's distance,which is represented under the area under the curve,how to find?
     
  9. Feb 22, 2007 #8
    You approximate the area using rectangles.

    If you know calculus then you can calculate the exact area in many cases by finding an antiderivative.
     
  10. Feb 22, 2007 #9
    You approximate the area using rectangles.

    If you know calculus then you can calculate the exact area in many cases by finding an antiderivative.
     
  11. Feb 22, 2007 #10

    inv

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    There's no equation given for the graph,how?
     
  12. Feb 22, 2007 #11

    inv

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    There's no equation given for the graph,how?
     
  13. Feb 22, 2007 #12
    Use the geometry of the curve to estimate the area. Do you have a digital camera to snap a picture of the graph?
     
  14. Feb 22, 2007 #13
    Use the geometry of the curve to estimate the area. Do you have a digital camera to snap a picture of the graph?
     
  15. Feb 22, 2007 #14

    Integral

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    A diagram would certinaly be nice!

    Can you segment the area under the graph into nice geometric regions? By that I mean triangles and rectangles?
     
  16. Feb 22, 2007 #15

    inv

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    I've just added the graph pic on the first post,edited.If u 1 ,refer to that 1.
     
    Last edited: Feb 23, 2007
  17. Feb 23, 2007 #16

    ZapperZ

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    This thread has been merged with another IDENTICAL question that the OP has cross-posted. So if it appears to make no sense at some spot, it isn't my fault.

    Zz.
     
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