How Accurate is Differential Approximation for Fourth Roots?

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The discussion focuses on approximating the fourth root of 17 using differential calculus. The initial calculation shows that using the differential method yields an approximation of 2.031, which is noted to have a significant error. To improve accuracy, participants suggest incorporating higher-order derivatives into the approximation. It is also mentioned that a smaller change (Δx) would enhance the approximation's reliability. Overall, the conversation emphasizes the limitations of using differentials for larger values of Δx in this context.
Karol
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Homework Statement


Approximate ##~\sqrt[4]{17}~## by use of differential

Homework Equations


Differential: ##~dy=f(x)~dx##

The Attempt at a Solution


$$y=\sqrt[4]{x},~~dy=\frac{1}{4}x^{-3/4}=\frac{1}{4\sqrt[4]{x^3}}$$
$$\sqrt[4]{16}=2,~~dx=1,~~dy=\frac{1}{4\sqrt[4]{x^2}}\cdot 1=0.149$$
$$\sqrt[4]{17}=2.031$$
The error is too big
 
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Karol said:

Homework Statement


Approximate ##~\sqrt[4]{17}~## by use of differential

Homework Equations


Differential: ##~dy=f(x)~dx##

The Attempt at a Solution


$$y=\sqrt[4]{x},~~dy=\frac{1}{4}x^{-3/4}=\frac{1}{4\sqrt[4]{x^3}}$$
$$\sqrt[4]{16}=2,~~dx=1,~~dy=\frac{1}{4\sqrt[4]{x^2}}\cdot 1=0.149$$
$$\sqrt[4]{17}=2.031$$
The error is too big

Nevertheless, your result is correct.

If you want better accuracy you need to take additional, higher order terms (2nd derivatives, maybe 3rd derivatives,etc).
 
Thank you Ray
 
Karol said:

Homework Statement


Approximate ##~\sqrt[4]{17}~## by use of differential

Homework Equations


Differential: ##~dy=f(x)~dx##

The Attempt at a Solution


$$y=\sqrt[4]{x},~~dy=\frac{1}{4}x^{-3/4}=\frac{1}{4\sqrt[4]{x^3}}$$
$$\sqrt[4]{16}=2,~~dx=1,~~dy=\frac{1}{4\sqrt[4]{x^2}}\cdot 1=0.149$$
$$\sqrt[4]{17}=2.031$$
The error is too big
Here is how I would write things.
##f(x + \Delta x) \approx f(x) + df \approx f(x) + f'(x) \Delta x = x^{1/4} + \frac 1 4 x^{-3/4} \Delta x##
When ##x = 16## and ##\Delta x = 1##, we have
##\sqrt[4]{16 + 1} \approx 16^{1/4} + \frac 1 4 \frac 1 {16^{3/4}} \cdot 1 = 2 + \frac 1 32 = 2.03125##
By calculator, ##\sqrt[4]{17} \approx 2.03054##. Since ##\Delta x = 1## is relatively large in comparison to x = 17, the approximation using differentials isn't all that accurate. If ##\Delta x## were smaller, the approximation would be better.
 
Thank you Mark44
By the way, how do i copy your names here, i write them again. when i pause the mouse on your name it becomes a pointer and there is no option to copy
 
Karol said:
Thank you Mark44
By the way, how do i copy your names here, i write them again. when i pause the mouse on your name it becomes a pointer and there is no option to copy
Just hit the 'Reply' button on the lower right of the post. You may also hite the 'Quote' button , also on the lower right.
BTW, small mistake: dy=f'(x)dx , not dy=f(x)dx , unless f(x)=f'(x).
 
Thanks, but i mean i want to copy your name, WWGD, to here, instead of looking and typing it. i usually thank every one that answered my question
 
Karol said:
Thanks, but i mean i want to copy your name, WWGD, to here, instead of looking and typing it. i usually thank every one that answered my question
Maybe you can just use the 'Like' button as a means of thanking.
 

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